具有多个LIKE值的SHOW TABLES语句

Question

mysql> SHOW TABLES like 'cms';
+-------------------------+
| Tables_in_tianyan (cms) |
+-------------------------+
| cms                     |
+-------------------------+
1 row in set (0.00 sec)

结果

mysql> SHOW TABLES like 'cms' or like 'role';
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual...

如何根据多个条件进行过滤？

Answer 1

您需要使用该WHERE子句.如文档中所示,如果使用"SHOW TABLES LIKE ...",则只能使用单个模式,但如果使用,则可以在WHERE子句中使用表达式"SHOW TABLES WHERE ...".由于您需要表达式,因此需要使用该WHERE子句.

SHOW TABLES
FROM `<yourdbname>`
WHERE 
    `Tables_in_<yourdbname>` LIKE '%cms%'
    OR `Tables_in_<yourdbname>` LIKE '%role%';

Answer 2

您可以使用普通的SQL WHERE语句来执行此操作.

SHOW TABLES WHERE Tables_in_tianyan LIKE '%cms%'

Answer 3

show tables from mydb 
where 
  Tables_in_mydb like '%statistics%' 
  or Tables_in_mydb like '%device%';