use*_*934 5 java java-8 java-stream collectors
根据Java 8 Docs
修饰符和类型:
<R,A> R
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方法和说明:
collect(Collector<? super T,A,R> collector)
Performs a mutable reduction operation on the elements of this stream using a Collector.
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修饰符和类型:
static <T,K> Collector<T,?,Map<K,List<T>>>
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方法和说明:
groupingBy(Function<? super T,? extends K> classifier)
Returns a Collector implementing a "group by" operation on input elements of type T, grouping elements according to a classification function, and returning the results in a Map.
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有人可以在这里解释泛型吗?T,K和R。我真的很困惑这种方法如何符合上面的签名:
List<Student> studentList = ....
Map<String, List<Student>> groupByTeachersMap = studentList.stream()
.collect(Collectors.groupingBy(Student::getTeachersName));
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Map<String, List<Student>>给定以上签名,我看不到collect如何返回。有人可以解释如何阅读此签名吗?
假设以下最小类:
class Student {
String teachersName;
public String getTeachersName() {
return teachersName;
}
}
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您可以通过在每个步骤中匹配输入和输出返回类型来关联您的代码。例如,签名为groupingBy:
// <T, K> Collector<T, ?, Map<K, List<T>>> groupingBy(Function<? super T, ? extends K> classifier)
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并且您的具体实现详述为:
Collectors.groupingBy(new Function<Student, String>() {
@Override
public String apply(Student student) {
return student.getTeachersName();
}
})
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在你的情况下返回
Collector<Student, ?, Map<String, List<Student>>>
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此外,如果您查看collect操作的签名,即
// <R, A> R collect(Collector<? super T, A, R> collector)
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因此,在您的情况下,返回R如下:
Map<String, List<Student>>
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