Tas*_*sos 8 sql t-sql sql-server sql-server-2008
我有一个以下格式的表格
Id StartDate EndDate Type
1 2012-02-18 2012-03-18 1
1 2012-03-17 2012-06-29 1
1 2012-06-27 2012-09-27 1
1 2014-08-23 2014-09-24 3
1 2014-09-23 2014-10-24 3
1 2014-10-23 2014-11-24 3
2 2015-07-04 2015-08-06 1
2 2015-08-04 2015-09-06 1
3 2013-11-01 2013-12-01 0
3 2018-01-09 2018-02-09 0
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我在这里找到了类似的问题,但没有找到可以帮助我解决问题的问题。我想合并具有相同行Id,Type和重叠的日期时间。
上表的结果应为
Id StartDate EndDate Type
1 2012-02-18 2012-09-27 1
1 2014-08-23 2014-11-24 3
2 2015-07-04 2015-09-06 1
3 2013-11-01 2013-12-01 0
3 2018-01-09 2018-02-09 0
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在另一台服务器上,我能够做到以下限制和以下查询:
Type列,而是在IdSELECT Id
, MIN(StartDate) AS StartDate
, MAX(EndDate) AS EndDate
FROM (
SELECT *
, SUM(CASE WHEN a.EndDate = a.StartDate THEN 0
ELSE 1
END
) OVER (ORDER BY Id, StartDate) sm
FROM (
SELECT Id
, StartDate
, EndDate
, LAG(EndDate, 1, NULL) OVER (PARTITION BY Id ORDER BY Id, EndDate) EndDate
FROM #temptable
) a
) b
GROUP BY Id, sm
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任何建议我怎么能
此方法使用附加的临时表来标识重叠日期的组,然后根据这些组执行快速汇总。
SELECT *, ROW_NUMBER() OVER (ORDER BY Id, Type) AS UID,
ROW_NUMBER() OVER (ORDER BY Id, Type) AS GroupId INTO #G FROM #TempTable
WHILE @@ROWCOUNT <> 0 BEGIN
UPDATE T1 SET
GroupId = T2.GroupId
FROM #G T1
INNER JOIN (
SELECT T1.UID, CASE WHEN T1.GroupId < T2.GroupId THEN T1.GroupId ELSE T2.GroupId END
FROM #G T1
LEFT OUTER JOIN #G T2
ON T1.Id = T2.Id AND T1.Type = T2.Type AND T1.GroupId <> T2.GroupId
AND T1.StartDate <= T2.EndDate AND T2.StartDate <= T1.EndDate
) T2 (UID, GroupId)
ON T1.UID = T2.UID
WHERE T1.GroupId <> T2.GroupId
END
SELECT Id, MIN(StartDate) AS StartDate, MAX(EndDate) AS EndDate, Type
FROM #G G GROUP BY GroupId, Id, Type
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这将返回期望值
Id StartDate EndDate Type
----------- ---------- ---------- -----------
1 2012-02-18 2012-09-27 1
1 2014-08-23 2014-11-24 3
2 2015-07-04 2015-09-06 1
3 2013-11-01 2013-12-01 0
3 2018-01-09 2018-02-09 0
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