Java实现JSON到XML的转换

Question

是否有现有的JAR可以从JSON转换为XML？

Answer 1

您可以创建一个JSONObject,然后使用org.json命名空间中的XML类将其转换为XML

将json字符串包装在对象中就像在构造函数中传递它一样简单

JSONObject o = new JSONObject(jsonString);

然后你可以使用XML类以XML格式获取它,如下所示:

String xml = org.json.XML.toString(o);

Answer 2

不是Java,而是纯XSLT 2.0实现:

看一看在f:json-document()从FXSL 2.x库.

使用此函数非常容易合并JSon并将其用作... XML.

例如,可以编写以下XPath表达式:

f:json-document($vstrParam)/Students/*[sex = 'Female']

并让所有的孩子Students用sex = 'Female'

这是完整的例子:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:xs="http://www.w3.org/2001/XMLSchema"
 xmlns:f="http://fxsl.sf.net/"
 exclude-result-prefixes="f xs"
 >
 <xsl:import href="../f/func-json-document.xsl"/>

 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:variable name="vstrParam" as="xs:string">
{

  "teacher":{
    "name":
      "Mr Borat",
    "age":
      "35",
    "Nationality":
      "Kazakhstan"
             },


  "Class":{
    "Semester":
      "Summer",
    "Room":
      null,
    "Subject":
      "Politics",
    "Notes":
      "We're happy, you happy?"
           },

  "Students":
    {
      "Smith":
        {"First Name":"Mary","sex":"Female"},
      "Brown":
        {"First Name":"John","sex":"Male"},
      "Jackson":
        {"First Name":"Jackie","sex":"Female"}
    }
    ,


  "Grades":

    {
      "Test":
      [
        {"grade":"A","points":68,"grade":"B","points":25,"grade":"C","points":15},

        {"grade":"C","points":2, "grade":"B","points":29, "grade":"A","points":55},

        {"grade":"C","points":2, "grade":"A","points":72, "grade":"A","points":65}
       ]
    }


}
 </xsl:variable>

 <xsl:template match="/">
    <xsl:sequence select=
     "f:json-document($vstrParam)/Students/*[sex = 'Female']"/>

 </xsl:template>
</xsl:stylesheet>

当上述转换应用于任何XML文档(忽略)时,将生成正确的结果:

<Smith>
   <First_Name>Mary</First_Name>
   <sex>Female</sex>
</Smith>
<Jackson>
   <First_Name>Jackie</First_Name>
   <sex>Female</sex>
</Jackson>