Baw*_*bak 5 javascript sorting json object ecmascript-6
我将编写一个函数,通过使用另一个对象作为其参数来确定根据哪个键执行哪种排序,以某种方式对任何JSON进行排序(仅知道它是对象的数组,例如产品列表)。
// The json that I get might looks like something like this.
// I just write one item of the array, but all of them are the same.
// But the blueprint of the items in each json are different.
const dataArray = [
{
id: 100,
name: 'product_1',
price: 99.95,
color: ['#fff', '#f0f', '#00f'],
category: ['cat_1', 'cat_2'],
booleanKey: true,
foo: {
foo1: 12,
foo2: 'string value',
foo3: {
foo3_1: 'string value',
foo3_2: 732.342
},
foo4: [
{
foo4_1_1: 853,
foo4_1_2: 24,
},
{
foo4_2_1: 'string value',
foo4_2_2: 435,
foo4_2_3: 25.35,
}
]
},
bar: {
bar1: {
bar1_1: 313,
bar1_2: 32.73
},
bar2: 75.3
}
}
];
// The function to sort the array
const sortData = obj => {
return dataArray.sort((a, b) => {
// Do something to return the correct value
});
}
// Sort array ascending by value 1, and descending by value -1
const result = sortData({foo: {foo3: {foo3_2: 1}}});
const anotherResult = sortData({bar: {bar2: -1}});
const anotherResult = sortData({price: 1});
Run Code Online (Sandbox Code Playgroud)
因为我必须编写一个函数来对具有任何结构的任何项目进行排序,所以我必须使用它们传递给我的obj作为基于该对象的键对数组进行排序的参数。
我发现此解决方案是这样的:
// The sample array that be used from the other answer
const fooArray = [
{ foo1: { foo2: { foo3: 123 } } },
{ foo1: { foo2: { foo3: 987 } } },
{ foo1: { foo2: { foo3: 456 } } },
{ foo1: { foo2: { foo3: 789 } } },
{ foo1: { foo2: { foo3: 321 } } },
{ foo1: { foo2: { foo3: 654 } } }
];
const sortData = obj => {
const pathArray = [];
while(typeof(obj) == 'object') {
pathArray.push(Object.keys(obj)[0]);
obj = obj[pathArray[pathArray.length - 1]];
}
const order = obj;
return fooArray.sort((a, b) => {
for(let pathKey of pathArray) {
a = a[pathKey];
b = b[pathKey];
}
return (a - b) * order;
});
}
const foo = sortData({ foo1: { foo2: { foo3: 1 } } });
Run Code Online (Sandbox Code Playgroud)
还有其他建议或想法吗?
const sortData = path => {
const sortOrder = query(path, path)
return dataArray.sort((a, b) => {
const valueOfA = query(a, path)
const valueOfB = query(b, path)
if (valueOfA < valueOfB) return -sortOrder
if (valueOfA > valueOfB) return sortOrder
return 0
})
}
Run Code Online (Sandbox Code Playgroud)
这里唯一复杂的事情是如何从另一个对象类型的参数中查询排序路径和顺序。
function query (target, path) {
const [key] = Object.keys(path)
if (typeof path[key] !== 'object') {
return target[key]
}
return query(path[key], target)
}
Run Code Online (Sandbox Code Playgroud)
let dataArray = [{id: 100}, {id: 200}]
const sortData = path => {
const sortOrder = query(path, path)
return dataArray.sort((a, b) => {
const valueOfA = query(a, path)
const valueOfB = query(b, path)
if (valueOfA < valueOfB) return -sortOrder
if (valueOfA > valueOfB) return sortOrder
return 0
})
}
console.log(sortData({id: 1})) // 100, 200
console.log(sortData({id: -1})) // 200, 100
dataArray = [
{foo: {bar: 'bar'}, a:'a', b:'b'},
{foo: {bar: 'car'}, a:'A', b:'B'}
]
console.log(sortData({foo: {bar: 1}})) // [...bar, ...car]
console.log(sortData({foo: {bar: -1}})) // [...car, ...bar]
function query (target, path) {
const [key] = Object.keys(path)
if (typeof path[key] !== 'object') {
return target[key]
}
return query(path[key], target)
}Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
91 次 |
| 最近记录: |