use*_*558 4 haskell haskell-lens
假设我有
data SumType = A | B | C
list = [A, B, B, A, C, A]
(as, rest) = span (\case A -> True; _ -> False) list
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假设我有棱镜_A,是否有一种方法可以更简洁地使用它来书写lens?
你可以说
(as, rest) = break (isn't _A) list
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isn't在Control.Lens.Prism中定义。不幸的是is' p = not . isn't p,尽管没有似乎相应的功能
(as, rest) = span (isRight . matching _A) list
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也可以。