Flutter 中 'Future<dynamic>' 的实例

Question

我从服务器获取一个 int Id，它在颤振的 HTTP 请求中，这没问题，我想将此值保存在一个变量中，但是当我调用返回值时，我收到此错误实例 'Future' ，有什么建议吗？ ? 这是代码

                    child: RaisedButton(onPressed:() {
                    CurrentPrjId= SaveProject();
                    print("CurrentPrjId Is saved CurrentPrjId :::::::: " );
                    print(CurrentPrjId);
                    Navigator.of(context).pushReplacementNamed('/AllUSerStories');
                }
//Save Project

  Future SaveProject() async {

//SaveProjectResult has the id of the current created project which i need that for its user stories
var SaveProjectResult = await GetPostProjects().createProject(_ProjectnameController.text, _CustomernameController.text, _dropNewItem, _dropNewItem2, _StartDateController.text, _EndDateController.text,);
print(":::::::::::::::::::::::::::::::The Project Is Created And Here Its ID In SaveProject:::::::::");
print(SaveProjectResult);
return SaveProjectResult;

}

Answer 1

没有你的代码，很难猜测，发生了什么..但你可能会尝试等待未来的完成..所以这样做：

methOdThatLoadsId().then((id) => print("Id that was loaded: $id"));

或者

var id = await methodThatLoadsId();

祝你好运 ：）