graphql 突变参数名称是 [对象：空原型]

Question

我尝试发布突变查询抛出我的nodejs基础grapqlapi。

我在服务器端的架构：

...
input PostPickProps {
  userId: String
  matchId: String
  predictionModelId: String
  modelVersionNumber: Int
  modelVariationIndex: Int
  pickEnd: String
}

type Mutation {
  postPick(props: PostPickProps): String
}
...

从应用程序查询：

export const postPick = async ({
  userId,
  matchId,
  predictionModelId,
  modelVersionNumber,
  modelVariationIndex,
  pickEnd
}) => {
  const res = await fetch(`
    mutation {
      postPick(props: {
        userId: "${userId}"
        matchId: "${matchId}"
        predictionModelId: "${predictionModelId}"
        modelVersionNumber: ${modelVersionNumber}
        modelVariationIndex: ${modelVariationIndex}
        pickEnd: "${pickEnd}"
      })
    }
  `)

  return res 
}

我在服务器端的解析器：

export const postPick = async ({ props }) => {
  const {
    pickEnd,
    matchId,
    userId,
    predictionModelId,
    modelVersionNumber,        
    modelVariationIndex,       
  } = props        

  console.log(props) // output [Object: null prototype] { userId: 'hack' ...}
  ...

console.log 输出不符合预期：

[Object: null prototype] {   
  userId: '5cb51b16e6161e6e5cb51b16',  
  matchId: '5cb51b16e6161e6e401262c2', 
 predictionModelId:'5ca0f4afb88b3a2e006faa0d',   ....

我怀疑获取在我的架构中声明的 props 对象。