使用STaX将xml转换为另一个xml需要花费大量时间

Question

我正在使用以下代码将大型xml流转换为另一个流:

 import java.io.ByteArrayInputStream;
 import java.io.InputStreamReader;
 import java.io.OutputStreamWriter;
 import java.io.PrintWriter;
 import java.io.Writer;
 import javax.xml.stream.XMLEventReader;
 import javax.xml.stream.XMLEventWriter;
 import javax.xml.stream.XMLInputFactory;
 import javax.xml.stream.XMLOutputFactory;
 import javax.xml.stream.XMLStreamException;
 import javax.xml.stream.XMLStreamReader;
 import javax.xml.stream.events.XMLEvent;
 import javax.xml.transform.Result;
 import javax.xml.transform.Source;
 import javax.xml.transform.Transformer;
 import javax.xml.transform.TransformerFactory;
 import javax.xml.transform.stax.StAXResult;
 import javax.xml.transform.stax.StAXSource;

 public class TryMe 
 {
   public static void main (final String[] args)
   {
    XMLInputFactory inputFactory = null;
    XMLEventReader eventReaderXSL = null;
    XMLEventReader eventReaderXML = null;
    XMLOutputFactory outputFactory = null;
    XMLEventWriter eventWriter = null;
    Source XSL = null;
    Source XML = null;
    inputFactory = XMLInputFactory.newInstance();
    outputFactory = XMLOutputFactory.newInstance();
    inputFactory.setProperty("javax.xml.stream.isSupportingExternalEntities", Boolean.TRUE);
    inputFactory.setProperty("javax.xml.stream.isNamespaceAware", Boolean.TRUE);
    inputFactory.setProperty("javax.xml.stream.isReplacingEntityReferences", Boolean.TRUE);
    try
    {
        eventReaderXSL = inputFactory.createXMLEventReader("my_template",
                new InputStreamReader(TryMe.class.getResourceAsStream("my_template.xsl")));
        eventReaderXML = inputFactory.createXMLEventReader("big_one", new InputStreamReader(
                TryMe.class.getResourceAsStream("big_one.xml")));
    }
    catch (final javax.xml.stream.XMLStreamException e)
    {
        System.out.println(e.getMessage());
    }

    // get a TransformerFactory object
    final TransformerFactory transfFactory = TransformerFactory.newInstance();

    // define the Source object for the stylesheet
    try
    {
        XSL = new StAXSource(eventReaderXSL);
    }
    catch (final javax.xml.stream.XMLStreamException e)
    {
        System.out.println(e.getMessage());
    }
    Transformer tran2 = null;
    // get a Transformer object
    try
    {

        tran2 = transfFactory.newTransformer(XSL);
    }
    catch (final javax.xml.transform.TransformerConfigurationException e)
    {
        System.out.println(e.getMessage());
    }

    // define the Source object for the XML document
    try
    {
        XML = new StAXSource(eventReaderXML);
    }
    catch (final javax.xml.stream.XMLStreamException e)
    {
        System.out.println(e.getMessage());
    }

    // create an XMLEventWriter object
    try
    {

        eventWriter = outputFactory.createXMLEventWriter(new OutputStreamWriter(System.out));
    }
    catch (final javax.xml.stream.XMLStreamException e)
    {
        System.out.println(e.getMessage());
    }

    // define the Result object
    final Result XML_r = new StAXResult(eventWriter);

    // call the transform method
    try
    {

        tran2.transform(XML, XML_r);
    }
    catch (final javax.xml.transform.TransformerException e)
    {
        System.out.println(e.getMessage());
    }

    // clean up
    try
    {
        eventReaderXSL.close();
        eventReaderXML.close();
        eventWriter.close();
    }
    catch (final javax.xml.stream.XMLStreamException e)
    {
        System.out.println(e.getMessage());
    }
}

}

my_template是这样的:

<xsl:stylesheet version = '1.0' 
     xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>

<xsl:preserve-space elements="*"/>

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>


<xsl:template match="@k8[parent::point]">
  <xsl:attribute name="k8">
    <xsl:value-of select="'xxxxxxxxxxxxxx'"/>
  </xsl:attribute>
</xsl:template>

</xsl:stylesheet>

和xml是一个很长的列表

<data>
  <point .... k8="blablabla" ... ></point>
  <point .... k8="blablabla" ... ></point>
  <point .... k8="blablabla" ... ></point>
  ....
  <point .... k8="blablabla" ... ></point>
</data>

如果我在处理输入流时使用身份转换器(使用tranfsFactory.newTransformer()而不是transFactory(XSL)),则会生成输出.而不是我的模板,没有办法..变换器读取所有输入,然后开始产生输出(当然,大量流经常会在结果之前出现内存不足.

任何的想法？？我吓坏了..我无法理解我的代码/ xslt中有什么问题

提前谢谢了!!

Answer 1

XSLT 1.0和2.0在完整XML的树数据模型上运行,因此XSLT 1.0和2.0处理器通常将完整的XML输入文档读入树中,然后创建一个随后序列化的结果树.您似乎假设使用StAX更改了XSLT的行为,但我不认为是这种情况,XSLT处理器构建树,因为stylessheet可能需要复杂的XPath导航器,如前面或前面的兄弟.

但是,当您使用Java时,您可以查看Saxon 9.3及其实验性XSLT 3.0流支持,这样您在处理非常大的XML输入文档时就不会耗尽内存.

XSLT中不常见的部分<xsl:template match="@k8[parent::point]">,通常只是简单编写,<xsl:template match="point/@k8">但您需要使用XSLT处理器测试是否会改变性能.