如何执行两个python列表的逐元素子结构?

Deb*_*anB -4 python python-3.x

我正在尝试创建一个新列表,执行两个 python 列表的逐元素子结构,如下所示:

from operator import add

number_villains_players = 0
villain_strength = []
player_strength = []
resulten_strength = []

def get_villain_strength(size):
    villain_strength = [int(x) for x in input("Enter {} numbers of space separated strength of Villains:".format(size)).split()]
    print(villain_strength)

def get_player_strength(size):

    player_strength = [int(x) for x in input("Enter {} numbers of space separated energy of Players:".format(size)).split()]
    print(player_strength)

def compare_strength():
    #resulten_strength = [m-n for (m,n) in zip(player_strength,villain_strength)]     #doesn't work
    #resulten_strength = [sum(x) for x in zip(player_strength, villain_strength)]     #doesn't work
    #resulten_strength = [list( map(add, player_strength, villain_strength) )]     #doesn't work
    resulten_strength = [a*b for a,b in zip(player_strength,villain_strength)]     #doesn't work
    print(resulten_strength)

def main():
    number_villains_players = input("How many Players/Villains?:")
    get_villain_strength(number_villains_players)
    get_player_strength(number_villains_players)
    compare_strength()
    if (i > 0 for i in resulten_strength):
        print("WIN")
    else:
        print("LOSE")

main()
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print(resulten_strength)始终为空作为[][[]]

我遵循了以下所有可能的解决方案:

谁能指出我哪里出错了?

knh*_*190 5

您在方法中分配本地列表,它们不是全局的。因此定义的顶行总是空的。这应该可以解决您的问题:

def get_villain_strength(size):
    global villain_strength
    villain_strength = [int(x) for x in input("Enter {} numbers of space separated strength of Villains:".format(size)).split()]
    print(villain_strength)
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然而,在任何地方使用全局变量都是不好的。你可能想要一个有返回值的函数。


当您在函数内分配相同名称的变量时,它将覆盖全局变量的名称,直到您从函数返回。或者说如果你查找一个变量,它首先在 中查找名称locals(),如果没有找到,它会去globals()。如果仍然没有找到,则会引发异常。