计算3个字典的乘积并连接键和值

Question

假设我有3种不同的字典：

dict1 = {
  "A": "a"
}

dict2 = {
  "B": "b", 
  "C": "c",
  "D": "d", 
  "E": "e"
}

dict3 = {
  "F": "f", 
  "G": "g"
}

我想计算这些字典（不含之间的产品的产品dict2和dict3），并结合了其中的键被连接与键和值_与值' and '

所需的输出将是一个字典：

{
  # dict1 x dict2 
  "A_B": "a and b", 
  "A_C": "a and c",
  "A_D": "a and d",
  "A_E": "a and e",

  # dict1 x dict3  
  "A_F": "a and f",
  "A_G": "a and g",

  # dict1 x dict2 x dict3 
  "A_B_F": "a and b and f",
  "A_B_G": "a and b and g",
  "A_C_F": "a and c and f",
  "A_C_G": "a and c and g",
  "A_D_F": "a and d and f",
  "A_D_G": "a and d and g",
  "A_E_F": "a and e and f",
  "A_E_G": "a and e and g"
} 

我查看了有关的文档，itertools但无法理解如何实现所需的输出。

Answer 1

将完成这项工作的功能是itertools.product。首先，这是打印产品的方法dict1 x dict2 x dict3：

for t in product(dict1.items(), dict2.items(), dict3.items()): 
     k, v = zip(*t) 
     print("_".join(k), "-", " and ".join(v))   

输出：

A_B_F - a and b and f
A_B_G - a and b and g
A_C_F - a and c and f
A_C_G - a and c and g
A_D_F - a and d and f
A_D_G - a and d and g
A_E_F - a and e and f
A_E_G - a and e and g

现在，只需填充一个result字典：

result = {}
for t in product(dict1.items(), dict2.items(), dict3.items()): 
     k, v = zip(*t) 
     result["_".join(k)] = " and ".join(v)

您现在可以将dict1 x dict2和dict1 x dict3更易于计算的产品添加到该词典中。

根据@ShadowRanger的评论，以下是完整的代码段：

import itertools
import pprint


dict1 = {
  "A": "a"
}

dict2 = {
  "B": "b",
  "C": "c",
  "D": "d",
  "E": "e"
}

dict3 = {
  "F": "f",
  "G": "g"
}


result = {}
for dicts in ((dict1, dict2), (dict1, dict3), (dict1, dict2, dict3)):
    for t in itertools.product(*(d.items() for d in dicts)):
        k, v = zip(*t)
        result["_".join(k)] = " and ".join(v)

pprint.pprint(result)

输出：

{'A_B': 'a and b',
 'A_B_F': 'a and b and f',
 'A_B_G': 'a and b and g',
 'A_C': 'a and c',
 'A_C_F': 'a and c and f',
 'A_C_G': 'a and c and g',
 'A_D': 'a and d',
 'A_D_F': 'a and d and f',
 'A_D_G': 'a and d and g',
 'A_E': 'a and e',
 'A_E_F': 'a and e and f',
 'A_E_G': 'a and e and g',
 'A_F': 'a and f',
 'A_G': 'a and g'}