Scrapy FormRequest 无法将复杂的字典作为 formdata 处理

Question

我正在尝试向 scrapy.FormRequest 对象提供表单数据。formdata 是以下结构的字典：

{
  "param1": [
    {
      "paramA": "valueA",
      "paramB": "valueB"
    }
  ]
}

通过相当于以下代码，在scrapy shell中运行：

from scrapy import FormRequest

url = 'www.example.com'
method_post = 'POST'
formdata = <the above dict>

fr = FormRequest(url=url, method=method_post, formdata=formdata)

fetch(fr)

作为回应，我收到以下错误：

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/Users/chhk/.local/share/virtualenvs/project/lib/python3.6/site-packages/scrapy/http/request/form.py", line 31, in __init__
    querystr = _urlencode(items, self.encoding)
  File "/Users/chhk/.local/share/virtualenvs/project/lib/python3.6/site-packages/scrapy/http/request/form.py", line 66, in _urlencode
    for k, vs in seq
  File "/Users/chhk/.local/share/virtualenvs/project/lib/python3.6/site-packages/scrapy/http/request/form.py", line 67, in <listcomp>
    for v in (vs if is_listlike(vs) else [vs])]
  File "/Users/chhk/.local/share/virtualenvs/project/lib/python3.6/site-packages/scrapy/utils/python.py", line 119, in to_bytes
    'object, got %s' % type(text).__name__)
TypeError: to_bytes must receive a unicode, str or bytes object, got dict

我尝试了各种解决方案，包括整个字符串，带有各种转义字符，以及 dict 的变体以使其更令人愉快，但是消除此错误的解决方案都不适用于请求（我得到 400回复）。

我知道 formdata 和我正在做的其他一切都是正确的，因为我已经在 curl 中成功复制了它（formdata 是通过 提供的-d formdata.txt）。

有没有办法解决 FormRequest 无法处理复杂的 dict 结构的问题？或者我错过了什么？

Answer 1

formdata您可以尝试使用body参数代替。例子：

FormRequest(url=url, method=method_post, body=json.dumps(formdata))