Dart：Dart 如何匹配类的构造函数中的命名参数？

Question

Dart 如何匹配类的构造函数中的命名参数？

示例（有效）：

Class MyWidget {

    final String a;
    final String b;

    MyWidget (
        @required this.a,
        @required this.b
    )

    @override // Yes, it's Flutter
    Widget build(BuildContext context) {
        return ....
    }
}


/// Calling MyWidget
return MyWidget(
    a: x,
    b: y
)

This works as expected. But in this setup I am forced to name the variable in MyWidget the same as the Named Parameter because the 'a' in the call is the same as the 'this.a' in the MyWidget.

What I would like is something like this:

Class MyWidget {

   final String aaa;
   final String bbb;

   MyWidget (
       @required a // And assign that value to this.aaa,
       @required b // And assign that value to this.bbb
   )
}

How do I assign the value of passed Named Parameter 'a' to local variable 'aaa'?

Answer 1

您必须this.xxx像这样权衡语法的简单性：

class MyWidget {
  final String aaa;
  final String bbb;

  MyWidget({a, b})
      : aaa = a,
        bbb = b;
}