当活动指示器视图可见时,不允许用户交互

Question

我有一个包含两个视图的视图.其中一个视图包含两个按钮和一些文本标签.另一个,alpha设置为0.25,有一个UIActivityIndicatorView告诉用户应用程序正在工作,他必须等到它完成.如果用户在UIActivityIndicatorView旋转时触摸按钮,则当UIActivityIndicatorView停止时,应用记住用户操作并响应它.如何丢弃UIActivityIndicatorView正在旋转时发生的用户交互？

谢谢阅读.

PD:就像在这个帖子中评论一样,我更喜欢不使用任何模态解决方案.

编辑:

我目前正在使用此代码,但它无法正常工作.

- (void)viewDidAppear:(BOOL)animated {

  // The view appears with an UIActivityIndicatorView spinning.
  [self showResults]; // The method that takes a long time to finish.
  [self.activityIndicator stopAnimating];
  // When the showResults method ends, the view shows the buttons to the user.
  [self.activityIndicatorView setHidden:YES];
  [self.menuButton setEnabled:YES];
  [self.menuButton setUserInteractionEnabled:YES];
  [self.playButton setEnabled:YES];
  [self.playButton setUserInteractionEnabled:YES];
  [self.view setUserInteractionEnabled:YES];
  [self.interactionView setUserInteractionEnabled:YES];
}

Answer 1

我发现这些方法非常有用:

[[UIApplication sharedApplication] beginIgnoringInteractionEvents];

[[UIApplication sharedApplication] endIgnoringInteractionEvents];

Answer 2

在Swift 3.0中要禁用交互：-

UIApplication.shared.beginIgnoringInteractionEvents()

恢复交互：-

UIApplication.shared.endIgnoringInteractionEvents()