在单个操作上启用多个HTTP方法?

Eri*_*ver 9 .net c# wcf web-services

我有一个操作合同(下面),我想允许GET和POST请求.如何告诉WCF接受单个OperationContract的两种类型的请求?

[OperationContract,
WebInvoke(Method="POST",
    BodyStyle = WebMessageBodyStyle.Bare,
    RequestFormat = WebMessageFormat.Xml,
    ResponseFormat = WebMessageFormat.Xml,
    UriTemplate = "query")]
XElement Query(string qry);

[OperationContract,
WebInvoke(Method="GET",
    BodyStyle = WebMessageBodyStyle.Bare,
    RequestFormat = WebMessageFormat.Xml,
    ResponseFormat = WebMessageFormat.Xml,
    UriTemplate = "query?query={qry}")]
XElement Query(string qry);
Run Code Online (Sandbox Code Playgroud)

Pre*_*ran 18

如果有人在寻找不同的解决方案,

[OperationContract]
[WebInvoke(Method="*")]
public <> DoWork()
{
     var method = WebOperationContext.Current.IncomingRequest.Method;
     if (method == "POST") return DoPost();
     else if (method == "GET") return DoGet();
     throw new ArgumentException("Method is not supported.");
}
Run Code Online (Sandbox Code Playgroud)


Eri*_*ver 5

这篇由Carlos FigueiraMSDN论坛上发布的帖子有一个解决方案.我现在就说这个,但如果有人有任何更清洁的解决方案让我知道.

[OperationContract,
WebInvoke(Method="POST",
    BodyStyle = WebMessageBodyStyle.Bare,
    RequestFormat = WebMessageFormat.Xml,
    ResponseFormat = WebMessageFormat.Xml,
    UriTemplate = "query")]
XElement Query_Post(string qry);

[OperationContract,
WebInvoke(Method="GET",
    BodyStyle = WebMessageBodyStyle.Bare,
    RequestFormat = WebMessageFormat.Xml,
    ResponseFormat = WebMessageFormat.Xml,
    UriTemplate = "query?query={qry}")]
XElement Query_Get(string qry);
Run Code Online (Sandbox Code Playgroud)