条件匹配时，对象数组返回对象

Question

我有一个数组，其值是ID，电子邮件和密码。

let array = [
 {id: hyu, email: a@a.com, password: 123},
 {id: rft, email: b@b.com, password: 456},
 {id: ght, email: c@c.com, password: 789},
 {id: kui, email: d@d.com, password: 679}
]

现在，我想在条件匹配时返回该对象。为此，我使用javascript some函数创建了一个函数，但是我想返回该对象，并且我们知道该some函数返回布尔值。

我不知道该怎么做。

我的代码是：

const isEmailExists = (email, array) => {
  return array.some(function(el) {
    return el.email === email;
  });
};

if (isEmailExists("c@c.com", array) == true) {
  // I want to work here with returned objects i.e on success case
} else {
  // error case
}

任何帮助都非常感谢

Answer 1

您可以利用.filter()并检查过滤后的数组的长度是否大于0：

let array = [
 {id: 'hyu', email: 'a@a.com', password: 123},
 {id: 'rft', email: 'b@b.com', password: 456},
 {id: 'ght', email: 'c@c.com', password: 789},
 {id: 'kui', email: 'd@d.com', password: 679}
]

let filtered = array.filter(row => row.email === 'a@a.com');

console.log(filtered);

if (filtered.length > 0) { /* mail exists */ }
else { /* mail does not exist */ }

Answer 2

假设电子邮件是唯一的，则可以使用find()。null如果不存在电子邮件，它将返回。

let array = [{"id":"hyu","email":"a@a.com","password":123},{"id":"rft","email":"b@b.com","password":456},{"id":"ght","email":"c@c.com","password":789},{"id":"kui","email":"d@d.com","password":679}];

const getObject = (email, array) => {
  return array.find(function(el) {
    return el.email === email;
  }) || null;
};

console.log(getObject("c@c.com", array));

短版：

const getObject = (email, array) => array.find(el => el.email === email ) || null;