android + pthread + c ++ = SIGSEGV

Question

以下代码在标准linux上编译和运行:

#include <iostream>
#include <pthread.h>

using namespace std;

class Foo
{
    public:
        Foo();
        void go_thread();
        void stop_thread();
    private:
        static void* worker( void* param );
        pthread_t m_pt;
};

Foo::Foo()
{
    m_pt = 0;
}

void Foo::go_thread()
{
    int success = pthread_create( &m_pt, NULL, worker, static_cast<void*>(this) );

    if( success == 0 )
    {
        cout << "thread started" << endl;
    }
}

void Foo::stop_thread()
{
    int success = pthread_join( m_pt, NULL );

    if( success == 0 )
    {
        cout << "thread stopped" << endl;
    }
}

void* Foo::worker( void* p )
{
    cout << "thread running" << endl;
    return 0;
}

int main()
{
    Foo f;
    f.go_thread();
    f.stop_thread();
    return 0;
}

并产生以下输出:

$ ./a.out
thread started
thread running
thread stopped
$

此代码也使用Android NDK(r5b)构建.但是,当我adb将生成的可执行文件推送到设备并运行它时,我会在main()运行之前得到一个SIGSEGV.我把这个问题分离出来pthread_create()似乎只是在我的代码中存在这个调用,从不介意执行,导致我的编程错误.有任何想法吗？

Answer 1

它可能不是这样但是尝试使pthread调用的函数创建一个普通的c函数(即声明它为extern"C")而不是静态成员函数:

这是因为从技术上讲,静态成员的调用约定可能与C库pthread使用的C调用约定不同(尽管很多时候它们是相同的(这就是它在你的linux盒子上运行的原因)我认为这不值得移植风险).

extern "C" void* start_the_thread(void*);

void* start_the_thread(void* data)
{
    Foo*  theObject = static_cast<Foo*>(data);
    // In Java if your Foo had been derived from Runable
    // This is s where theObject->run() would have been called.
    return Foo::worker(data);
}

int success = pthread_create( &m_pt, NULL, start_the_thread, static_cast<void*>(this)