Shi*_*har 6 java android retrofit retrofit2
Retrofit 2.0 的一个非常令人失望的特性是它不能准确地说明解析响应失败的地方。因此,在邮递员中,当我使用相同的正文点击请求时,我得到的登录响应为:
{
"result": "success",
"response_code": 200,
"data": {
"id": "1",
"display_name": "admin",
"email": "payal@teckmovers.com",
"username": "admin",
"access_token": "8daa8e02ca432e51ae90912fbf63eeea"
}
}
Run Code Online (Sandbox Code Playgroud)
但是当我在 Retrofit 中使用完全相同的 body 发出完全相同的请求时,我得到了一个非常奇怪的响应:{protocol=http/1.1, code=200, message=OK, url= http://192.168.0.52/evidya /wp-api/v1/user/login }。现在我已经通过上述问题解决了其他相关问题,但没有一个对我有用。请帮忙。我的代码:
改造API接口:
public interface eVidyaApi {
@FormUrlEncoded
@POST("user/login")
Call<LoginResponse> loginUser(
@HeaderMap Map<String, String> headers,
@Field("email") String email,
@Field("password") String password
);
}
Run Code Online (Sandbox Code Playgroud)
登录功能:
public void login() {
Log.d(TAG, "Login");
if (!validate()) {
onLoginFailed();
return;
}
final ProgressDialog progressDialog = new ProgressDialog(LoginActivity.this, R.style.MyDialogTheme);
progressDialog.setIndeterminate(true);
progressDialog.setMessage("Authenticating...");
progressDialog.show();
String email = _emailText.getText().toString();
String password = _passwordText.getText().toString();
Log.d(TAG, "login: "+email+" "+password);
// TODO: Implement your own authentication logic here.
Call<LoginResponse> loginResponseCall = evidya.loginUser(Common.getHeaders(), email, password);
loginResponseCall.enqueue(new Callback<LoginResponse>() {
@Override
public void onResponse(Call<LoginResponse> call, Response<LoginResponse> response) {
progressDialog.dismiss();
if(!response.isSuccessful()){
Toast.makeText(LoginActivity.this, ""+response.message(), Toast.LENGTH_SHORT).show();
Log.d(TAG, "onResponse: fail "+response.code());
return;
}
Log.d(TAG, "onResponse: success"+response.code()+" "+response);
if(response.body()!=null){
String content="";
// _loginButton.setEnabled(false);
LoginResponse loginResponse = response.body();
content += "code:"+ response.code();
content += "token:"+ loginResponse.getData().getAccessToken();
content += "result"+ loginResponse.getResult();
content += "result"+ loginResponse.getData().getDisplayName();
// onLoginSuccess();
Log.d(TAG, "onResponse: login res"+content);
} else {
Toast.makeText(LoginActivity.this, "Invalid response from server", Toast.LENGTH_SHORT).show();
}
}
@Override
public void onFailure(Call<LoginResponse> call, Throwable t) {
progressDialog.dismiss();
Toast.makeText(LoginActivity.this, "Cannot fetch request", Toast.LENGTH_SHORT).show();
}
});
}
Run Code Online (Sandbox Code Playgroud)
登录响应.java
package com.example.evidya.Retrofit.Model.LoginModel;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;
public class LoginResponse {
@SerializedName("result")
@Expose
private String result;
@SerializedName("response_code")
@Expose
private Integer responseCode;
@SerializedName("data")
@Expose
private Data data;
public String getResult() {
return result;
}
public void setResult(String result) {
this.result = result;
}
public Integer getResponseCode() {
return responseCode;
}
public void setResponseCode(Integer responseCode) {
this.responseCode = responseCode;
}
public Data getData() {
return data;
}
public void setData(Data data) {
this.data = data;
}
}
Run Code Online (Sandbox Code Playgroud)
数据.java
package com.example.evidya.Retrofit.Model.LoginModel;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;
public class Data {
@SerializedName("id")
@Expose
private String id;
@SerializedName("display_name")
@Expose
private String displayName;
@SerializedName("email")
@Expose
private String email;
@SerializedName("username")
@Expose
private String username;
@SerializedName("access_token")
@Expose
private String accessToken;
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getDisplayName() {
return displayName;
}
public void setDisplayName(String displayName) {
this.displayName = displayName;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getAccessToken() {
return accessToken;
}
public void setAccessToken(String accessToken) {
this.accessToken = accessToken;
}
}
Run Code Online (Sandbox Code Playgroud)
我的日志记录(ok hhttp),当点击登录按钮错误的细节时:
我的日志记录(好的 hhttp),当单击带有正确详细信息的登录按钮时:
基本上问题是我 Log.d(TAG, "onResponse: success"+response.code()+" "+response);用来检查 onresponse 回调中的响应。而我应该做的就是不要卡在那里并检查 loginResponse 对象的值(来自LoginResponse loginResponse = response.body();)。因为 response.body 实际上是以对象形式存储响应的。这就是改造中的工作方式。
根据您的日志,API 调用正确。它也会响应。但问题是您后端的 API 身份验证失败。添加登录您的网络服务并检查。从应用程序方面来看,它运行良好。这不是改造的问题。
使用以下更新您的 onResponse() 并运行应用程序。然后测试并让我知道您收到什么消息。
if(response.body()!=null){
LoginResponse loginResponse = response.body();
String content="";
if (response.body().getResponseCode()==200){
content+= loginResponse.getData().getAccessToken();
content+= loginResponse.getData().getDisplayName();
content+= loginResponse.getData().getEmail();
content+= loginResponse.getData().getId();
content+= loginResponse.getData().getUsername();
}else{
content+=loginResponse.getData().getMsg();
}
Log.d(TAG, "onResponse: login res"+content);
} else {
Toast.makeText(LoginActivity.this, "Invalid response from server", Toast.LENGTH_SHORT).show();
}
Run Code Online (Sandbox Code Playgroud)
下面是 Data.java 中的代码
@SerializedName("msg")
@Expose
private String msg;
public String getMsg() {
return msg;
}
public void setMsg(String msg) {
this.msg = msg;
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
5080 次 |
| 最近记录: |