Can I abbreviate df[ !is.na(df$val) & df$val > 15]?

Question

I have a dataframe from which I want to extract the records where the value in val is greater than 15 and those whose val is not NA:

 df[ !is.na(df$val) & df$val > 15, ]

Since I assume that such a comparison is often needed in R, I am wondering if this comparison can be abbreviated somewow. In fact, I'd not be surprised if this question is already asked on StackOverflow - but I was unable to come up with a search that found it.

Answer 1

subset omits NA values and also avoids repeating df:

subset(df, val > 15)

which also eliminates NA values but df must be repeated:

df[which(df$val > 15), ]

The dplyr package's filter is like base subset:

library(dplyr)

df %>% filter(val > 15)

Using sqldf the NA values are dropped.

library(sqldf)

sqldf("select * from df where val > 15")