在Hibernate 3.2.2的本机sql查询中使用IN子句

car*_*lsz 12 sql hibernate in-operator sql-in

以类似于此处发现的问题的方式:在本机sql查询中使用IN子句 ; 我试图IN()通过Hibernate中的本机SQL查询来使用子句.虽然另一个问题的作者能够使用JPA,但我不是.另外,我坚持使用版本3.2.2.

似乎Hibernate本身不支持,IN()因为它在应用查询参数时试图将我的ID列表(长基元数组)转换为二进制形式:query.setParameter("publisherGroups", [1243536264532,1243536264533,1243536264535]);

来自Hibernate:

SELECT sum(C2CReportedConversion) as c2CConversion, sum(C2CReportedRevenue) as c2CRevenue, sum(I2CReportedConversion) as i2CConversion, sum(I2CReportedRevenue) as i2CRevenue, sum(Clicks) as clicks, sum(Impressions) as impressions, sum(Requests) as requests, sum(Views) as views, coalesce(Name, DisplayName) FROM UiTemplateReportingCache JOIN AdUnit USING (AdUnitId) WHERE PublisherId = ? AND PublisherGroupId IN ( ? ) AND Date >= ? AND Date <= ? GROUP BY coalesce(Name, DisplayName)

从mysql日志:

SELECT sum(C2CReportedConversion) as c2CConversion, sum(C2CReportedRevenue) as c2CRevenue, sum(I2CReportedConversion) as i2CConversion, sum(I2CReportedRevenue) as i2CRevenue, sum(Clicks) as clicks, sum(Impressions) as impressions, sum(Requests) as requests, sum(Views) as views, coalesce(Name, DisplayName) FROM UiTemplateReportingCache JOIN AdUnit USING (AdUnitId) WHERE PublisherId = 1239660230591 AND PublisherGroupId IN (_binary'??\0ur\0[Jx ??u?\0\0xp\0\0\0 \0\0!???T\0\0!???U\0\0!???W\0\0!???m\0\0!???n\0\0!???t\0\0!???{\0\0!???|\0\0!???}\0\0!???~\0\0#??\0\0$|??S') AND Date >= '2011-03-17 00:00:00' AND Date <= '2011-03-18 23:59:59' GROUP BY coalesce(Name, DisplayName)

注意_binary启动IN()值的部分.这项工作的诀窍是什么?我正在使用的Hibernate版本是否会这样做?如果没有,我有什么替代品?

提前致谢,

卡尔

car*_*lsz 33

回答了我自己的问题,在发布之前应该有RTFM."技巧"是使用query.setParameterList()而不是query.setParameter().