从 python3 中的 .wav 文件中删除文件头

Question

我一直在做一个使用 RSA 算法加密 .wav 文件的项目，为此，我需要删除文件头才能正确读取文件。我需要将声音数据作为 numpy 数组。现在我在网上搜索了这个，但不明白什么是文件头以及如何在 python3 中删除它。期待建议。谢谢。

Answer 1

binarySound = bytearray()
binaryHeader = bytearray()

with open("a2002011001-e02.wav",'rb') as f:
        binaryHeader = f.read(44)
        binarySound = f.read()

这应该就是您要寻找的。这会将前 44 个字节（应该是标头）读入binaryHeader变量，并将其余声音数据读入binarySound变量。

要恢复您的音乐文件，您只需将这两个文件重新添加到一起即可

song = bytearray()

with open("header.bin","rb") as h:
        song = h.read()
        with open("data.bin","rb") as d:
                song += d.read()

with open("new.wav","wb") as f:
        f.write(song)

编辑：要在 OP 中包含编辑以满足 numpy 数组的需要：

import numpy

binarySound = {}
binaryHeader = {}

song = {}

with open("a2002011001-e02.wav",'rb') as f:
        buffer = f.read(44)
        binaryHeader = numpy.frombuffer(buffer,dtype=numpy.uint8)
        buffer = f.read()
        binarySound = numpy.frombuffer(buffer,dtype=numpy.uint8)

with open("header.bin","wb") as f:
        f.write(binaryHeader)

with open("data.bin","wb") as f:
        f.write(binarySound)

with open("header.bin","rb") as h:
        song = h.read()
        with open("data.bin","rb") as d:
                song += d.read()

with open("new.wav","wb") as f:
        song = numpy.array(song)
        f.write(song.tobytes())