smi*_*324 2 python unicode google-app-engine
有没有办法用App Engine的BlobStore存储unicode数据(在Python中)?
我正在保存这样的数据
file_name = files.blobstore.create(mime_type='application/octet-stream')
with files.open(file_name, 'a') as f:
f.write('<as><a>' + '</a><a>'.join(stringInUnicode) + '</a></as>')
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但是在生产(非开发)服务器上我遇到了这个错误.它似乎是将我的Unicode转换为ASCII,我不知道为什么.
为什么要尝试转换回ASCII?我可以避免这个吗?
Traceback (most recent call last):
File "/base/data/home/apps/myapp/1.349473606437967000/myfile.py", line 137, in get
f.write('<as><a>' + '</a><a>'.join(stringInUnicode) + '</a></as>')
File "/base/python_runtime/python_lib/versions/1/google/appengine/api/files/file.py", line 364, in write
self._make_rpc_call_with_retry('Append', request, response)
File "/base/python_runtime/python_lib/versions/1/google/appengine/api/files/file.py", line 472, in _make_rpc_call_with_retry
_make_call(method, request, response)
File "/base/python_runtime/python_lib/versions/1/google/appengine/api/files/file.py", line 226, in _make_call
rpc.make_call(method, request, response)
File "/base/python_runtime/python_lib/versions/1/google/appengine/api/apiproxy_stub_map.py", line 509, in make_call
self.__rpc.MakeCall(self.__service, method, request, response)
File "/base/python_runtime/python_lib/versions/1/google/appengine/api/apiproxy_rpc.py", line 115, in MakeCall
self._MakeCallImpl()
File "/base/python_runtime/python_lib/versions/1/google/appengine/runtime/apiproxy.py", line 161, in _MakeCallImpl
self.request.Output(e)
File "/base/python_runtime/python_lib/versions/1/google/net/proto/ProtocolBuffer.py", line 204, in Output
self.OutputUnchecked(e)
File "/base/python_runtime/python_lib/versions/1/google/appengine/api/files/file_service_pb.py", line 2390, in OutputUnchecked
out.putPrefixedString(self.data_)
File "/base/python_runtime/python_lib/versions/1/google/net/proto/ProtocolBuffer.py", line 432, in putPrefixedString
v = str(v)
UnicodeEncodeError: 'ascii' codec can't encode character u'\xe9' in position 313: ordinal not in range(128)
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BLOB存储包含二进制数据:字节,而不是字符.因此,您将不得不进行某种编码步骤.utf-8看起来像任何编码一样好.
f.write('<as><a>' + '</a><a>'.join(stringInUnicode) + '</a></as>')
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如果在一个项目这会出问题stringInUnicode包含<,&或]]>序列.您需要进行一些转义(使用适当的XML库来序列化数据,或手动):
with files.open(file_name, 'a') as f:
f.write('<as>')
for line in stringInUnicode:
line= line.replace(u'&', u'&').replace(u'<', u'<').replace(u'>', u'>');
f.write('<a>%s</a>' % line.encode('utf-8'))
f.write('</as>')
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(如果字符串包含控制字符,这仍然是格式不正确的XML,但是你没有那么多可以做到这一点.如果你需要在XML中存储任意二进制文件,你需要一些特殊的编码,如base- 64位在上面.)