gue*_*tli 3 python excel openpyxl
此 Python 代码失败:
from openpyxl import Workbook
wb = Workbook()
sheet = wb.create_sheet('*nice*')
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例外:
/home/foo/local/bin/python /home/foo/src/invalid.py
Traceback (most recent call last):
File "/home/foo/src/invalid.py", line 5, in <module>
sheet = wb.create_sheet('*nice')
File "/home/foo/local/lib/python2.7/site-packages/openpyxl/workbook/workbook.py", line 158, in create_sheet
new_ws = Worksheet(parent=self, title=title)
File "/home/foo/local/lib/python2.7/site-packages/openpyxl/worksheet/worksheet.py", line 121, in __init__
_WorkbookChild.__init__(self, parent, title)
File "/home/foo/local/lib/python2.7/site-packages/openpyxl/workbook/child.py", line 50, in __init__
self.title = title or self._default_title
File "/home/foo/local/lib/python2.7/site-packages/openpyxl/workbook/child.py", line 93, in title
raise ValueError(msg)
ValueError: Invalid character * found in sheet title
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如何创建包含*标题的工作表?
您可以使用正则表达式来替换无效字符:
import re
from openpyxl import Workbook
from openpyxl.workbook.child import INVALID_TITLE_REGEX
wb = Workbook()
title = re.sub(INVALID_TITLE_REGEX, '_', '*nice*')
sheet = wb.create_sheet(title)
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但这不是解决方案,只是一种解决方法。
欢迎更好的解决方案:有没有办法引用*?
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