数组看起来像
products = [
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c9485d37804946bc487ce59",
},
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c94862a7804946bc487ce5e",
},
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c9486397804946bc487ce61",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c9485d37804946bc487ce59",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c94862a7804946bc487ce5e",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c9486397804946bc487ce61",
}
]
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当我尝试使用id="5c94aa7b7a37631ce2a97a72"和仅删除一项material="5c9485d37804946bc487ce59"
我使用过滤功能
filtered = products.filter(x => x.id !== id && x.material !== material);
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它将删除所有具有这些ID和材料的产品。在此功能中设置条件的正确方法是什么?
只需使用||代替&&,这样两个条件都必须为false才能使filter回调返回false:
const products = [{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c9485d37804946bc487ce59",
},
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c94862a7804946bc487ce5e",
},
{
"id": "5c94aa7b7a37631ce2a97a72",
"material": "5c9486397804946bc487ce61",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c9485d37804946bc487ce59",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c94862a7804946bc487ce5e",
},
{
"id": "5c94a0a87a37631ce2a979de",
"material": "5c9486397804946bc487ce61",
}
];
console.log(products.length);
const id = "5c94aa7b7a37631ce2a97a72";
const material = "5c9485d37804946bc487ce59";
const filtered = products.filter(x => x.id !== id || x.material !== material);
console.log(filtered.length);
console.log(filtered);Run Code Online (Sandbox Code Playgroud)