如何在不加载 Laravel 对象的情况下获取关系计数

Question

我有一个模范客户，它有很多项目。我想在不包括其对象的情况下查找项目数。

客户模型包括：

public function numberOfProjects()
{
    return $this->hasMany(Project::class)->count();
}

在我的控制器中查询：

 $customers = Customer::where(['is_active'=>1])
                                ->with(['customerContactInformation'=> function ($query) {
                                    $query->where('is_active',1);
                                }, 'numberOfProjects'])
                                ->skip($skip)->take(10)
                                 ->get();

它给了我错误：在整数上调用成员函数 addEagerConstraints()

Answer 1

尝试这个

客户模型

public function numberOfProjects()
{
    return $this->hasMany(Project::class);
}

控制器

$customers = Customer::where(['is_active'=>1])
                    ->with(['customerContactInformation'=> function ($query) {
                        $query->where('is_active',1);
                    }])
                    ->withCount('numberOfProjects') //you can get count using this
                    ->skip($skip)
                    ->take(10)
                    ->get();

那应该是工作

$customers = Customer::withCount('numberOfProjects')->get();

WithCount 在特定状态

$customers = Customer::withCount([
                        'numberOfProjects',
                        'numberOfProjects as approved_count' => function ($query) {
                            $query->where('approved', true);
                        }
                    ])
                    ->get();