从C++宏创建字符串列表和枚举列表

Tia*_*ago 19 c c++ macros variadic c-preprocessor

为了使我的代码更短更容易更改,我想替换类似的东西

enum{ E_AAA, E_BBB, E_CCC };
static const char *strings{"AAA", "BBB", "CCC" };
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使用宏,如INIT(AAA,BBB,CCC); 但是当我尝试使用变量参数和字符串化做一个宏时,我得到一个错误,因为没有声明参数.

有关如何做到这一点的任何想法?

Dr *_*eco 27

这是我几天前学到的解决方案.参加您的问题的简化版本是:

#define ENUM_MACRO(name, v1, v2, v3, v4, v5, v6, v7)\
    enum name { v1, v2, v3, v4, v5, v6, v7};\
    const char *name##Strings[] = { #v1, #v2, #v3, #v4, #v5, #v6, #v7};

ENUM_MACRO(Week, Sun, Mon, Tue, Wed, Thu, Fri, Sat);
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但是你可以使用函数调用来改进版本,如下所示:

#define ENUM_MACRO(name, v1, v2, v3, v4, v5, v6, v7)\
    enum name { v1, v2, v3, v4, v5, v6, v7};\
    const char *name##Strings[] = { #v1, #v2, #v3, #v4, #v5, #v6, #v7};\
    const char *name##ToString(value) { return name##Strings[value]; }

ENUM_MACRO(Week, Sun, Mon, Tue, Wed, Thu, Fri, Sat);
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这将成长为:

  enum Week { Sun, Mon, Tue, Wed, Thu, Fri, Sat}; 
  const char *WeekStrings[] = { "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat"}; 
  const char *WeekToString(value) { return WeekStrings[value]; };
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您甚至可以为第一个元素使用偏移量,如下所示:

#define ENUM_MACRO(name, offset, v1, v2, v3, v4, v5, v6, v7)\
    enum name { v1 =  offset, v2, v3, v4, v5, v6, v7};\
    const char *name##Strings[] = { #v1, #v2, #v3, #v4, #v5, #v6, #v7};\
    const char *name##ToString(value) { return name##Strings[value - offset ]; }

ENUM_MACRO(Week, 1, Sun, Mon, Tue, Wed, Thu, Fri, Sat);
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我希望这有帮助.

小心,Beco

参考:

打印月份问题,由Kush,Danny Varod回答


Sco*_*ley 14

你可以用一些宏魔法来做到这一点:

#define FRUITS \
    etype(Unknown), \
    etype(Apple),   \
    etype(Orange),  \
    etype(Banana),  \
    etype(Apricot), \
    etype(Mango)

#define etype(x) F_##x

typedef enum { FRUITS } Fruit;

#undef etype
#define etype(x) #x

static const char *strFruit[] = { FRUITS };
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这是一个测试程序:

#include <iostream>
#include <exception>
#include <vector>

#define FRUITS \
    etype(Unknown), \
    etype(Apple),   \
    etype(Orange),  \
    etype(Banana),  \
    etype(Apricot), \
    etype(Mango)

#define etype(x) F_##x

typedef enum { FRUITS } Fruit;

#undef etype
#define etype(x) #x

static const char *strFruit[] = { FRUITS };

const char *enum2str (Fruit f)
{
    return strFruit[static_cast<int>(f)];
}

Fruit str2enum (const char *f)
{
    const int n = sizeof(strFruit) / sizeof(strFruit[0]);
    for (int i = 0; i < n; ++i)
    {
        if (strcmp(strFruit[i], f) == 0)
            return (Fruit) i;
    }
    return F_Unknown;
}

int main (int argc, char *argv[])
{
    std::cout << "I like " << enum2str(F_Mango) << std::endl;
    std::cout << "I do not like " << enum2str(F_Banana) << std::endl;
    std::vector<char *> v;
    v.push_back("Apple");
    v.push_back("Mango");
    v.push_back("Tomato");
    for (int i = 0; i < v.size(); ++i)
    {
        const Fruit f = str2enum(v[i]);
        if (f == F_Unknown)
            std::cout << "Is " << v[i] << " a fruit?" << std::endl;
        else
            std::cout << v[i] << " is a fruit" << std::endl;
    }
    return 0;
}
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它输出:

I like Mango
I do not like Banana
Apple is a fruit
Mango is a fruit
Is Tomato a fruit?
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小智 11

这是我的解决方案:

#define FRUITS(fruit) \
  fruit(Apple)        \
  fruit(Orange)       \
  fruit(Banana)       

#define CREATE_ENUM(name) \
  F_##name,

#define CREATE_STRINGS(name) \
  #name,
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诀窍在于,"水果"是宏"水果"的一个参数,将被你传递给它的东西取代.例如:

FRUITS(CREATE_ENUM)
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将扩展到这个:

F_Apple, F_Orange, F_Banana, 
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让我们创建枚举和字符串数组:

enum fruit {
  FRUITS(CREATE_ENUM)
};

const char* fruit_names[] = {
  FRUITS(CREATE_STRINGS)
};
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Chr*_*man 6

一种方法是使用X-Macros,它基本上是一种定义宏的方法,然后用于生成比简单宏容易允许的更复杂的结构。 这是一个完全按照您的要求执行的示例


Beg*_*oth 5

这是Boost.Preprocessor的解决方案:

#include <boost/preprocessor.hpp>

#define DEFINE_ENUM_DECL_VAL(r, name, val) BOOST_PP_CAT(name, BOOST_PP_CAT(_, val))
#define DEFINE_ENUM_VAL_STR(r, name, val) BOOST_PP_STRINGIZE(val)
#define DEFINE_ENUM(name, val_seq)                                                 \
  enum name {                                                                      \
    BOOST_PP_SEQ_ENUM(BOOST_PP_SEQ_TRANSFORM(DEFINE_ENUM_DECL_VAL, name, val_seq)) \
  };                                                                               \
  static const char* BOOST_PP_CAT(name, _strings[] = ) {                           \
    BOOST_PP_SEQ_ENUM(BOOST_PP_SEQ_TRANSFORM(DEFINE_ENUM_VAL_STR, name, val_seq)) \
  };

DEFINE_ENUM(E, (AAA)(BBB)(CCC))
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(AAA)(BBB)(CCC)是树元素AAA,BBB和CCC的Boost.Preprocessor序列;宏将枚举名称附加到其模态中:

enum E { E_AAA, E_BBB, E_CCC };
static const char* E_strings[] = { "AAA", "BBB", "CCC" };
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