Ruby中的Lambda 1.9

Question

我没有遵循这个改变.从:

longest_path_first = lambda do |host, location, _, _|

至:

longest_path_first = lambda do |(host, location, _, _)|

谁能解释一下？

Answer 1

>> al = lambda { |a,b,c| b }
>> bl = lambda { |(a,b,c)| b }
>> list = [[1,1,1], [2,2,2], [3,3,3], [4,0,4]]
>> list.sort_by &al
ArgumentError: wrong number of arguments (1 for 3)
    from (irb):1:in `block in irb_binding'
    from (irb):4:in `each'
    from (irb):4:in `sort_by'
>> list.sort_by &bl
 => [[4, 0, 4], [1, 1, 1], [2, 2, 2], [3, 3, 3]] 

有点说明他们为什么这样做了.

Ruby发生变化的原因是他们试图让lambda与普通方法保持一致:

>> def test(a,b,c); b; end
>> test [1,2,3]
ArgumentError: wrong number of arguments (1 for 3)
    from (irb):16:in `test'

绕过不完全漂亮的语法的好方法是使用新的闪亮的Stab运算符^tm:

cl = ->(a, b, c) { b }