Ruby创建递归目录树

Question

我需要递归遍历一个目录并创建一个与jsTree控件一起使用的树.控件接受像这样的JSON格式.我需要一些红宝石魔法才能让它干净而迅速地完成.

任何帮助表示赞赏.

Answer 1

你可能想要这样的东西(未经测试):

def directory_hash(path, name=nil)
  data = {:data => (name || path)}
  data[:children] = children = []
  Dir.foreach(path) do |entry|
    next if (entry == '..' || entry == '.')
    full_path = File.join(path, entry)
    if File.directory?(full_path)
      children << directory_hash(full_path, entry)
    else
      children << entry
    end
  end
  return data
end

递归地走下树,建立一个哈希.用你最喜欢的序列化库把它变成json.

Answer 2

首先取出树,将其转换为叶子路径列表,类似于:

def leaves_paths tree
  if tree[:children]
    tree[:children].inject([]){|acc, c|
      leaves_paths(c).each{|p|
        acc += [[tree[:name]] + p]
      }
      acc
    }
  else
    [[tree[:name]]]
  end
end

(不确定上面是否完全符合您的jsTree结构,但原理是相同的.)

这是输入和输出的示例:

tree = {name: 'foo', children: [
      {name: 'bar'},
      {name: 'baz', children: [
        {name: 'boo'}, 
        {name: 'zoo', children: [
          {name: 'goo'}
        ]}
      ]}
    ]}

p leaves_paths tree
#=> [["foo", "bar"], ["foo", "baz", "boo"], ["foo", "baz", "zoo", "goo"]]

然后,对于每条路径,请致电FileUtils#mkdir_p:

paths = leaves_paths tree
paths.each do |path|
  FileUtils.mkdir_p(File.join(*path))
end

你应该没问题.

编辑:更简单的版本:

您不需要创建叶子列表,只需遍历整个树并为每个节点创建一个目录:

# executes block on each tree node, recursively, passing the path to the block as argument
def traverse_with_path tree, path = [], &block
  path += [tree[:name]]
  yield path
  tree[:children].each{|c| traverse_with_path c, path, &block} if tree[:children]
end

traverse_with_path tree do |path|
  FileUtils.mkdir(File.join(*path))
end

EDIT2:

哦,对不起,我误会了.所以,这是一种基于磁盘上的目录树制作哈希的方法:

Dir.glob('**/*'). # get all files below current dir
  select{|f|
    File.directory?(f) # only directories we need
  }.map{|path|
    path.split '/' # split to parts
  }.inject({}){|acc, path| # start with empty hash
    path.inject(acc) do |acc2,dir| # for each path part, create a child of current node
      acc2[dir] ||= {} # and pass it as new current node
    end
    acc
  }

因此,对于以下结构:

#$ mkdir -p foo/bar
#$ mkdir -p baz/boo/bee
#$ mkdir -p baz/goo

上面的代码返回此哈希:

{
  "baz"=>{
    "boo"=>{
      "bee"=>{}},
    "goo"=>{}},
  "foo"=>{
    "bar"=>{}}}

希望你能够满足你的需求.