Eve*_*e11 6 python parameters valueerror
我是新手
我想防止每次人们注册时出现重复的用户名。
这是我截取的代码:
def submit(self):
username_info = username.get()
username_password = password.get()
#connect to db
db = mysql.connector.connect(host = 'localhost', user = 'root', password = '', database = 'user')
#create a cursor
mycursor = db.cursor()
#insert to db
sql = ("INSERT INTO useraccess (user_type, password) VALUES (%s, %s)")
query = (username_info, username_password)
mycursor.execute(sql, query)
#commit
db.commit()
#create a messagebox
messagebox.showinfo("Registration", "Successfully Register")
#if username has been used
find_user = ("SELECT * FROM useraccess WHERE user_type = ?")
user_query = (username_info)
mycursor.execute(find_user, user_query)
#if (username == username_info):
if mycursor.fetchall():
messagebox.showerror("Registration", "The username chosen is already used. Please select another username")
else:
messagebox.showinfo("Registration", "Account Created!")
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但是每次运行,虽然已经在db中注册了用户名,但是只显示创建成功的消息框和错误:
ValueError: 无法处理参数。
任何人都可以帮我解决这个问题吗?
jcb*_*bsv 14
我相信问题的根源就在这条线上
user_query = (username_info)
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它应该是
user_query = (username_info,)
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尾随逗号是括号中的表达式和元组之间的语法差异。
代码的另一个问题是查询:
find_user = ("SELECT * FROM useraccess WHERE user_type = ?")
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应该是:
find_user = ("SELECT * FROM useraccess WHERE user_type = %s")
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