获取超过 100 条消息

Question

我试图找出一种方法来使用循环来获取使用fetchMesasges()和之前不和谐的旧消息。我想使用循环获得超过 100 个限制，但我无法弄清楚，我能找到的每篇文章都只讨论如何使用循环删除超过 100 个限制，我只需要检索它们。

我是编码和 javascript 的新手，所以我希望有人能给我一个正确的方向。

这是我能够设法检索超过 100 条消息的唯一方法（在多次尝试使用循环失败后）：

channel.fetchMessages({ limit: 100 })
    .then(msg => {
        let toBeArray = msg;
        let firstLastPost = toBeArray.last().id;

        receivedMessage.channel
            .fetchMessages({ limit: 100, before: firstLastPost })
            .then(msg => {
                let secondToBeArray = msg;
                let secondLastPost = secondToBeArray.last().id;

                receivedMessage.channel
                    .fetchMessages({ limit: 100, before: secondLastPost })
                    .then(msg => {
                        let thirdArray = msg;
                        let thirdLastPost = thirdArray.last().id;

                        receivedMessage.channel
                            .fetchMessages({ limit: 100, before: thirdLastPost })
                            .then(msg => {
                                let fourthArray = msg;
                            });
                    });
            });
    });

Answer 1

您可以做的是使用async/await 函数和循环来发出顺序请求

async function lots_of_messages_getter(channel, limit = 500) {
    const sum_messages = [];
    let last_id;

    while (true) {
        const options = { limit: 100 };
        if (last_id) {
            options.before = last_id;
        }

        const messages = await channel.fetchMessages(options);
        sum_messages.push(...messages.array());
        last_id = messages.last().id;

        if (messages.size != 100 || sum_messages >= limit) {
            break;
        }
    }

    return sum_messages;
}