gdb无法进入printf

Question

这是我的示例程序:

#include<stdio.h>

int main()
{

printf("hello good morning \n");
return 0;
}


gcc -Wall -g temp.c


/opt/langtools/bin/gdb a.out
HP gdb 3.3 for PA-RISC 1.1 or 2.0 (narrow), HP-UX 11.00.
Copyright 1986 - 2001 Free Software Foundation, Inc.
Hewlett-Packard Wildebeest 3.3 (based on GDB) is covered by the
GNU General Public License. Type "show copying" to see the conditions to
change it and/or distribute copies. Type "show warranty" for warranty/support.
..
(gdb) b 6
Breakpoint 1 at 0x2b14: file temp.c, line 6.
(gdb) run
Starting program: /oo_dgfqausr/test/dfqwrk4/temp/a.out

Breakpoint 1, main () at temp.c:6
6       printf("hello good morning \n");
(gdb) step
hello good morning
7       return 0;
(gdb)

一旦我尝试进入printf function.its退出并返回main.这是否意味着定义了printf函数的shred库没有提供调试符号？或者我做错了什么？

Answer 1

这意味着printf没有可用的源/调试符号.您可以使用stepi步入printf无论如何,你只有使用拆卸(使用disas命令).