如何在python中整齐地处理几个regexp案例

Question

所以我在python中得到了一些我需要使用regexp解析的输入.

目前我正在使用这样的东西:

matchOK = re.compile(r'^OK\s+(\w+)\s+(\w+)$')
matchFailed = re.compile(r'^FAILED\s(\w+)$')
#.... a bunch more regexps

for l in big_input:
  match = matchOK.search(l)
  if match:
     #do something with match
     continue
  match = matchFailed.search(l)
  if match:
     #do something with match
     continue
  #.... a bunch more of these 
  # Then some error handling if nothing matches

现在我通常喜欢python因为它简洁而简洁.但这感觉很冗长.我希望能够做到这样的事情:

for l in big_input:      
  if match = matchOK.search(l):
     #do something with match     
  elif match = matchFailed.search(l):
     #do something with match 
  #.... a bunch more of these
  else
    # error handling

我错过了什么,或者是第一个形式像我将要得到的那样整洁？

Answer 1

class helper:
    def __call__(self, match):
        self.match= match
        return bool(match)

h= helper()
for l in big_input:      
    if h(matchOK.search(l)):
        # do something with h.match     
    elif h(matchFailed.search(l)):
        # do something with h.match 
    ... # a bunch more of these
    else:
        # error handling

或匹配器作为类方法：

class matcher:
    def __init__(self):
        # compile matchers
        self.ok= ...
        self.failed= ...
        self....= ...

    def matchOK(self, l):
        self.match= self.ok(l)
        return bool(self.match)

    def matchFailed(self, l):
        self.match= self.failed(l)
        return bool(self.match)

    def match...(self, l):
        ...

m= matcher()
for l in big_input:      
    if m.matchOK(l):
        # do something with m.match     
    elif m.matchFailed(l):
        # do something with m.match 
    ... # a bunch more of these
    else:
        # error handling