Conditional operator for an operator

Question

I have a piece of code:

if (foo > bar) {
    baz = foo - bar
} else {
    baz = foo + bar
}

I have a question if I can somehow shorten this code to a single line, something like

PSEUDOCODE:

baz = foo (foo > bar ? + : -) bar

Real code I'd like to shorten

if (gradientStartH > gradientEndH) {
    h = gradientStartH - Math.abs(gradientStartH - gradientEndH) / arr.length * i
} else {
    h = gradientStartH + Math.abs(gradientStartH - gradientEndH) / arr.length * i
}

Thanks!

Answer 1

You could convert the check to a number or take -1 as factor.

baz = foo + (foo > bar || -1) * bar

The cleanest approach is to use an object with the operands and a check for getting the operands.

op = {
    true: function (a, b) { return a + b; }, // add
    false: function (a, b) { return a - b; } // sub
}
baz = op[foo > bar](foo, bar);

Answer 2

像这样的事情，

baz = foo > bar ? foo - bar : foo + bar