在ActiveResource查询中禁用嵌入对象中的json根元素

min*_*bug 8 json ruby-on-rails activeresource ruby-on-rails-3

我在嵌入式json对象中遇到了不必要的根元素问题.这是清理过的来源:

用户模型:

class User < ActiveResource::Base
      self.format = :json
      self.element_name = "user"
      #...
end
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控制者的行动'新'

def new
 @user = User.build
 @user.id = nil
end
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User.build给了我下一个json:

{
  "id":0,
  "user_name":null,
  "credit_card":
    {"number":null}
}
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控制者的行动'创造'

def create
    @user = User.new(params[:user])
    @user.save
end
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查看'_form.html.erb'

<%= form_for(@user) do |f| %>
    <%= f.label :user_name %>
    <%= f.text_field :user_name %>

        <%= f.fields_for @user.credit_card do |cc_f| %>
            <%= cc_f.label :number %>
            <%= cc_f.text_field :number %>
        <% end %>
<% end %>
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当我保存用户app时发送下一个json:

{
 "user"=>
   {"credit_card"=>
     {"credit_card"=>
       {"number"=>"xxxxyyyyzzzzaaaa"}
     }, 
   "user_name"=>"test"
    }, 
 "api_client_key"=>"top_secret"
}
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问题在于重复credit_card密钥.我怎么解决呢?


最终解决方案

class User < ActiveResource::Base
      self.include_root_in_json = false
      self.format = :json
      self.element_name = "user"

      def to_json(options = {})
          {
             self.class.element_name => self.attributes
          }.to_json(options)
      end
# ...
end
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感谢Oliver Barnes

oli*_*nes 11

尝试

ActiveResource::Base.include_root_in_json = false
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如果您需要保留顶部根并只删除关联的信用卡对象的根,那么您可能需要使用#to_json自定义json输出,如下所示:

def to_json(options = {})
  { "user"=>
      {"credit_card"=>
        {"number"=> self.credit_card.number }
       }, 
        "user_name"=> self.user_name
   }.to_json(options)
end
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  • @ mind.debug,如果您需要顶级根但不需要关联的根,则可能需要使用as_json自定义输出.现在将其添加到答案中 (3认同)