在Python中跳过迭代

Question

我有一个循环,但有可能在循环内引发异常.这当然会一起阻止我的程序.为了防止我捕获异常并处理它们.但是,即使发生异常,迭代的其余部分也会运行.在我的except:子句中是否有一个关键字可以跳过当前迭代的其余部分？

Answer 1

你正在寻找继续.

Answer 2

for i in iterator:
    try:
        # Do something.
        pass
    except:
        # Continue to next iteration.
        continue

Answer 3

像这样的东西？

for i in xrange( someBigNumber ):
    try:
        doSomethingThatMightFail()
    except SomeException, e:
        continue
    doSomethingWhenNothingFailed()

Answer 4

继续示例:

number = 0

for number in range(10):
   number = number + 1

   if number == 5:
      continue    # continue here

   print('Number is ' + str(number))

print('Out of loop')

输出:

Number is 1
Number is 2
Number is 3
Number is 4
Number is 6 # Note: 5 is skipped!!
Number is 7
Number is 8
Number is 9
Number is 10
Out of loop

Answer 5

我想你正在寻找继续

Answer 6

对于此特定用例，使用try..except..else是最干净的解决方案，else如果未引发异常，则将执行该子句。

注意：该else子句必须跟在所有except子句之后

for i in iterator:
    try:
        # Do something.
    except:
        # Handle exception
    else:
        # Continue doing something