Mar*_*cin 3 javascript css-selectors puppeteer apify
可以说我给出的情况像这个页面
<div id="details-container" class="style-scope ytd-channel-about-metadata-renderer">
<yt-formatted-string class="subheadline style-scope ytd-channel-about-metadata-renderer">Details</yt-formatted-string>
<table class="style-scope ytd-channel-about-metadata-renderer">
<tbody class="style-scope ytd-channel-about-metadata-renderer"><tr class="style-scope ytd-channel-about-metadata-renderer">
<td class="label style-scope ytd-channel-about-metadata-renderer">
<yt-formatted-string class="style-scope ytd-channel-about-metadata-renderer"></yt-formatted-string>
</td>
<td class="style-scope ytd-channel-about-metadata-renderer">
<ytd-button-renderer align-by-text="" class="style-scope ytd-channel-about-metadata-renderer" button-renderer=""></ytd-button-renderer>
<div id="captcha-container" class="style-scope ytd-channel-about-metadata-renderer"></div>
<div id="email-container" class="style-scope ytd-channel-about-metadata-renderer"></div>
<a id="email" target="_blank" class="style-scope ytd-channel-about-metadata-renderer" href="mailto:undefined" hidden=""></a>
</td>
</tr>
<tr class="style-scope ytd-channel-about-metadata-renderer">
<td class="label style-scope ytd-channel-about-metadata-renderer">
<yt-formatted-string class="style-scope ytd-channel-about-metadata-renderer"><span class="deemphasize style-scope yt-formatted-string"> Location: </span></yt-formatted-string>
</td>
<td class="style-scope ytd-channel-about-metadata-renderer">
<yt-formatted-string class="style-scope ytd-channel-about-metadata-renderer">YourCountry</yt-formatted-string>
</td>
</tr>
</tbody></table>
</div>
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假设我需要获取“YourCountry”,我实际上如何获取此元素?
到目前为止我尝试过:
const location = await page.$$eval(
"#details-container > table > tbody:nth-child(1) > tr:nth-child(1) > yt-formatted-string",
locationEl => locationEl.innerHTML
);
console.log(location) // Undefined
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不知道该怎么做,尝试只返回 tr 然后再次评估 tr[1] 不起作用,因为它说 tr 没有函数 .$$eval。
请注意,我正在使用 apify 来获取页面。
在您提供的 HTML 中,您想要的元素是第二个元素下yt-formatted-string
第二个元素的直接子元素,但您尝试将其与第二个元素的直接子元素匹配。您需要修复您的选择器。例如:td
tr
yt-formatted-string
tr
console.log("HTML:", document.querySelector("#details-container > table > tbody > tr:nth-child(2) > td:nth-child(2) > yt-formatted-string").innerHTML)
Run Code Online (Sandbox Code Playgroud)\r\n<div id="details-container" class="style-scope ytd-channel-about-metadata-renderer">\r\n <yt-formatted-string class="subheadline style-scope ytd-channel-about-metadata-renderer">Details</yt-formatted-string>\r\n <table class="style-scope ytd-channel-about-metadata-renderer">\r\n <tbody class="style-scope ytd-channel-about-metadata-renderer">\r\n <tr class="style-scope ytd-channel-about-metadata-renderer">\r\n <td class="label style-scope ytd-channel-about-metadata-renderer">\r\n <yt-formatted-string class="style-scope ytd-channel-about-metadata-renderer"></yt-formatted-string>\r\n </td>\r\n <td class="style-scope ytd-channel-about-metadata-renderer">\r\n <ytd-button-renderer align-by-text="" class="style-scope ytd-channel-about-metadata-renderer" button-renderer=""></ytd-button-renderer>\r\n <div id="captcha-container" class="style-scope ytd-channel-about-metadata-renderer"></div>\r\n <div id="email-container" class="style-scope ytd-channel-about-metadata-renderer"></div>\r\n <a id="email" target="_blank" class="style-scope ytd-channel-about-metadata-renderer" href="mailto:undefined" hidden=""></a>\r\n </td>\r\n </tr>\r\n <tr class="style-scope ytd-channel-about-metadata-renderer">\r\n <td class="label style-scope ytd-channel-about-metadata-renderer">\r\n <yt-formatted-string class="style-scope ytd-channel-about-metadata-renderer"><span class="deemphasize style-scope yt-formatted-string"> Location: </span></yt-formatted-string>\r\n </td>\r\n <td class="style-scope ytd-channel-about-metadata-renderer">\r\n <yt-formatted-string class="style-scope ytd-channel-about-metadata-renderer">YourCountry</yt-formatted-string>\r\n </td>\r\n </tr>\r\n </tbody>\r\n </table>\r\n</div>
Run Code Online (Sandbox Code Playgroud)\r\n并且您应该能够调用$$eval
&c。如果你有一个ElementHandle
. 问题是你的选择器\xe2\x80\x99不匹配,所以你没有\xe2\x80\x99t。
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