响应 CreateAPIView DRF

Question

我想要CreateAPIView这样的回复

Response(
            {
                'status': status_code.HTTP_200_OK,
                'message': 'Testimonials fetched',
                'data': serializer.data
             },)

但我不知道最好在内部使用哪个函数AddAPIView来获得上述响应

class AddAPIView(generics.CreateAPIView):
    queryset = Masjid.objects.all()
    serializer_class = serializers.MasjidAddSerialzer
    permission_classes = [IsAuthenticated]

Answer 1

覆盖视图类的create()方法AddAPIView

class AddAPIView(generics.CreateAPIView):
        queryset = Masjid.objects.all()
        serializer_class = serializers.MasjidAddSerialzer
        permission_classes = [IsAuthenticated]

    def create(self, request, *args, **kwargs):
        response = super().create(request, *args, **kwargs)
        return Response({
            'status': 200,
            'message': 'Testimonials fetched',
            'data': response.data
        })