我有两个类 PizzasState 和 ToppingsState。PizzaState 已经有选择器来获取选定的披萨。
@State<PizzaStateModel>({
name: 'pizzas',
defaults: initialState
})
export class PizzasState {
constructor(private pizzaService: PizzasService) {
}
@Selector([RouterState])
static getSelectedPizza(
state: PizzaStateModel,
routerState: RouterStateModel<RouterStateParams>
): Pizza {
const pizzaId = routerState.state && routerState.state.params.pizzaId;
return pizzaId && state.entities[pizzaId];
}
@Selector()
getPizzaVisualized(state: PizzaStateModel): Pizza {
//
// what is here?
//
}
}
Run Code Online (Sandbox Code Playgroud)
并且 ToppingsState 已选择 Toppings
@State({
name: 'toppings',
defaults: initialState
})
export class ToppingsState {
constructor(private toppingsService: ToppingsService) {
}
@Selector()
static selectedToppings(state: ToppingsStateModel): number[] {
return state.selectedToppings;
}
Run Code Online (Sandbox Code Playgroud)
现在我想将我选择的披萨与选定的配料一起加入,并得到我的可视化披萨。
如何正确重用 getSelectedPizza 和 getSelectedToppings ?谢谢
看起来您需要使用连接选择器。
@Selector([ToppingsState.selectedToppings])
getPizzaVisualized(state: PizzaStateModel, selectedToppings: number[]): Pizza {
// User data from both states.
}
Run Code Online (Sandbox Code Playgroud)