Fal*_*son 9 typescript reactjs
initialState出现错误:类型为'{email:string; 密码:字符串;有效:布尔值;}'不可分配给'never'类型的参数。ts(2345)
function reducer(state: IState, action: IFluxAction) {
const Users = UsersFetch()
switch (action.type) {
case 'email':
const email = action.value
const valid = Users.find(e => e === email) ? true : false
return {
email,
valid,
}
case 'password':
const password = action.value
return {
password,
}
default:
throw new Error()
}
}
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const initialState = {
email: '',
password: '',
valid: false,
}
const [state, dispatch] = React.useReducer(reducer, initialState)
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键入此错误以满足错误的正确方法是什么?
React 16.8.1 打字稿3.3.1
应该(通过固定)
添加...state到收益中,例如
switch (action.type) {
case 'email':
const email = action.value
const valid = Users.find(e => e === email) ? true : false
return {
...state,
email,
valid,
}
case 'password':
const password = action.value
return {
...state,
password,
}
default:
throw new Error()
}
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此外,正如@madflanderz所建议的那样,将IState设置为减速器的预期返回值有助于解决此类问题。
小智 24
我也为这个问题而苦苦挣扎。在我看来,预防错误的最佳方法似乎是将State Interface添加为reducer的返回类型。然后,您可以在化简器内看到类型错误,而不是在useReducer行上。
像这样:
function reducer(state: IState, action: IFluxAction): IState {
// reducer code
// type errors are visible here
}
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谢谢,疯狂弗兰德斯!
我遇到过同样的问题。就我而言,问题是我错过了输入减速器的返回值:
function reducer(state: IState, action: IFluxAction): IState /<- *Don't forget this!*/ {
// reducer code
// type errors are visible here
}
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该问题最有可能与您的减速器声明有关。该initialState的类型必须是相同的减速功能状态的类型和返回值。
这将起作用:
function reducer(state: {email: string}) {
return state
}
const initialState = {
email: '',
}
const [state, dispatch] = React.useReducer(reducer, initialState)
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这将产生一个错误:
// state has a different type than initialState.
function reducer(state: {address: string}) {
// No return statement.
}
const initialState = {
email: '',
}
const [state, dispatch] = React.useReducer(reducer, initialState) // Error
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在作出反应的类型,你可以看到的是,useReducer通用的函数总是期望initialState类型是一个的ReducerState<R>类型。该ReducerState<R>是一种有条件的类型,试图推断出正确的状态的类型和回退到never如果失败。
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