UWP：DataGrid、MenuFlyout 右键单击

Question

问题： 当右键单击一行时，我试图在 DataGrid 上创建一个菜单。

目标： 是否可以在右键单击一行时在 DataGrid 上创建菜单；我可以在一个单元格上创建一个吗？

<controls:DataGridTemplateColumn Header="OrderId">
    <controls:DataGridTemplateColumn.CellTemplate>
        <DataTemplate>
            <Grid>
                <Grid.ContextFlyout>
                    <MenuFlyout>
                        <MenuFlyoutItem Text="Copy" Icon="Copy" Click="MenuFlyoutItem_Copy" />
                        <MenuFlyoutSeparator />
                        <MenuFlyoutItem Text="Delete" Icon="Delete" Click="MenuFlyoutItem_Delete" />
                    </MenuFlyout>
                </Grid.ContextFlyout>
                <TextBlock Text="{Binding OrderId}" />
            </Grid>
        </DataTemplate>
    </controls:DataGridTemplateColumn.CellTemplate>
</controls:DataGridTemplateColumn>

private void MenuFlyoutItem_Copy(object sender, RoutedEventArgs e)
{
    ObservableCollection<SampleOrder> dataGrid = DataGrid.ItemsSource as ObservableCollection<SampleOrder>;

    MenuFlyoutItem mfi = sender as MenuFlyoutItem;
    SampleOrder seleted = mfi.DataContext as SampleOrder;

    var copiedItem = (SampleOrder)seleted.Clone();

    dataGrid.Add(copiedItem);
}

private void MenuFlyoutItem_Delete(object sender, RoutedEventArgs e)
{
    ObservableCollection<SampleOrder> dataGrid = DataGrid.ItemsSource as ObservableCollection<SampleOrder>;

    MenuFlyoutItem mfi = sender as MenuFlyoutItem;
    SampleOrder seleted = mfi.DataContext as SampleOrder;

    dataGrid.Remove(seleted);
}

Answer 1

除非我遗漏了什么，否则这比 Nico 的回答容易得多。您需要做的就是RowStyle像这样设置属性：

<controls:DataGrid.RowStyle>
    <Style TargetType="controls:DataGridRow">
        <Setter Property="controls:DataGridRow.ContextFlyout">
            <Setter.Value>
                <MenuFlyout>
                    <MenuFlyoutItem x:Name="MyMenuItem"
                                    Click="MyMenuItem_Click"
                                    Text="Do Things" />
                </MenuFlyout>
            </Setter.Value>
        </Setter>
    </Style>
</controls:DataGrid.RowStyle>

然后在您的处理程序中：

private void MyMenuItem_Click(object sender, RoutedEventArgs e)
{
    var item = (sender as FrameworkElement).DataContext as MyModel;
    // Do things with your item.
}