使用迭代器遍历列表？

Question

我需要使用C++遍历列表的示例.

Answer 1

您的问题的示例如下

  #include <iostream>
  #include <list>
  using namespace std;

  typedef list<int> IntegerList;
  int main()
  {
      IntegerList    intList;
      for (int i = 1; i <= 10; ++i)
         intList.push_back(i * 2);
      for (IntegerList::const_iterator ci = intList.begin(); ci != intList.end(); ++ci)
         cout << *ci << " ";
      return 0;
  }

Answer 2

为了反映C++中的新增内容并通过@karthik扩展一些过时的解决方案,从C++ 11开始,可以使用auto说明符缩短它:

#include <iostream>
#include <list>
using namespace std;

typedef list<int> IntegerList;

int main()
{
  IntegerList intList;
  for (int i=1; i<=10; ++i)
   intList.push_back(i * 2);
  for (auto ci = intList.begin(); ci != intList.end(); ++ci)
   cout << *ci << " ";
}

或者更容易使用范围为基础的循环:

#include <iostream>
#include <list>
using namespace std;

typedef list<int> IntegerList;

int main()
{
    IntegerList intList;
    for (int i=1; i<=10; ++i)
        intList.push_back(i * 2);
    for (int i : intList)
        cout << i << " ";
}

Answer 3

如果您的意思是STL std::list,那么这里有一个简单的例子来自http://www.cplusplus.com/reference/stl/list/begin/.

// list::begin
#include <iostream>
#include <list>

int main ()
{
  int myints[] = {75,23,65,42,13};
  std::list<int> mylist (myints,myints+5);

  std::cout << "mylist contains:";
  for (std::list<int>::iterator it=mylist.begin(); it != mylist.end(); ++it)
    std::cout << ' ' << *it;

  std::cout << '\n';

  return 0;
}