Jim*_*mmy 6 javascript reactjs jestjs redux redux-thunk
我正试图用我们的redux动作实现开玩笑.鉴于以下操作foo并且它正在进行以下测试,以下测试失败,因为store.getActions()它只是按照我[{"type": "ACTION_ONE"}]的意愿返回[{"type": "ACTION_ONE"}, {"type": "ACTION_TWO"}].如何在测试时获得两个调度操作?谢谢!
import configureMockStore from 'redux-mock-store';
import thunk from 'redux-thunk';
export const foo = () => {
return (dispatch) => {
dispatch(actionOne());
return HttpService.get(`api/sampleUrl`)
.then(json => dispatch(actionTwo(json.data)))
.catch(error => handleError(error));
};
};
const middlewares = [thunk];
const mockStore = configureMockStore(middlewares);
beforeEach(() => {
store = mockStore({});
});
describe('sample test', () => {
test('validates foo complex action', () => {
const expectedActions = [
{type: actionTypes.ACTION_ONE},
{type: actionTypes.ACTION_TWO},
];
return store.dispatch(actions.foo())
.then(() => {
expect(store.getActions())
.toEqual(expectedActions);
});
});
});
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您没有模拟API调用,因为没有模拟就不会成功,因此不会触发promise解析时调度的操作.您可以使用fetchMock模拟API调用.正确执行此操作后,您的测试将起作用
import configureMockStore from 'redux-mock-store';
import thunk from 'redux-thunk';
import fetchMock from 'fetch-mock';
import fetch from 'node-fetch';
export const foo = () => {
return (dispatch) => {
dispatch(actionOne());
return fetch(`api/sampleUrl`)
.then(r => r.json())
.then(json => dispatch(actionTwo(json)))
.catch(error => handleError(error));
};
};
const middlewares = [thunk];
const mockStore = configureMockStore(middlewares);
beforeEach(() => {
store = mockStore({});
fetchMock.restore()
});
describe('sample test', () => {
test('validates foo complex action', () => {
fetchMock.getOnce('api/sampleUrl', {
body: { sample: ['do something'] }
})
const expectedActions = [
{type: actionTypes.ACTION_ONE},
{type: actionTypes.ACTION_TWO},
];
return store.dispatch(actions.foo())
.then(() => {
expect(store.getActions())
.toEqual(expectedActions);
});
});
});
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