JS 过滤数组的数组

Question

我正在尝试过滤数组的数组。

我已经搜索了 SO 的答案，但我遇到的所有问题都与我的不匹配（对象数组或未嵌套的简单数组或格式不同等......）

将值存储在数组中后，它们看起来像这样：

[[Paris, One ONE, Boss, Wed Mar 01 00:00:00 GMT+01:00 2017, ], [Paris, Two TWO, Temp, Sat Jul 01 00:00:00 GMT+02:00 2017, ], [Paris, Three THREE, Employee, Sat Sep 01 00:00:00 GMT+02:00 2018, ], [Paris, Four FOUR, Intern, Thu Nov 01 00:00:00 GMT+01:00 2018, ], [Paris, Five FIVE, N.A., Sat Dec 01 00:00:00 GMT+01:00 2018, ], [Paris, Six SIX, Director, Tue Jan 01 00:00:00 GMT+01:00 2019, ], [Paris, Seven SEVEN, Director, Fri Jan 01 00:00:00 GMT+01:00 2016, Sun Jul 01 00:00:00 GMT+02:00 2018], [Paris, Eight EIGHT, Director, Fri Jan 01 00:00:00 GMT+01:00 2016, Sun Oct 01 00:00:00 GMT+02:00 2017], [Paris, Nine NINE, N.A., Thu Nov 01 00:00:00 GMT+01:00 2018, Sat Dec 01 00:00:00 GMT+01:00 2018], [London, Ten TEN, Employee, Fri Jan 01 00:00:00 GMT+01:00 2016, Mon Oct 01 00:00:00 GMT+02:00 2018], [London, Eleven ELEVEN, Intern, Mon Feb 01 00:00:00 GMT+01:00 2016, Mon Jan 01 00:00:00 GMT+01:00 2018], [London, Twelve TWELVE, Employee, Sun May 01 00:00:00 GMT+02:00 2016, Sun Oct 01 00:00:00 GMT+02:00 2017]]

我希望能够过滤这一数组，并将数据仅链接到一个社区，例如巴黎。

我该怎么做呢？

非常感谢你的帮助

Answer 1

你可以使用Array.filter，像这样：

const data = [
['Paris', 'One ONE', 'Boss', 'Wed Mar 01 00:00:00 GMT+01:00 2017' ],
['Paris', 'Two TWO', 'Temp', 'Sat Jul 01 00:00:00 GMT+02:00 2017' ],
['London', 'Three THREE', 'Employee, Sat Sep 01 00:00:00 GMT+02:00 2018' ]];

const result = data.filter(function(item) { return item[0]==='Paris'});
// const result = data.filter(item => item[0]==='Paris'); // ES6
console.log(result);

Answer 2

假设数组中的所有元素都是Strings，您只需检查数组数组中的每个数组是否都包含该元素Paris。

const yourArray = [
  ['Paris', 'one One', 'whatever else'],
  ['Paris', 'one One', 'whatever else'],
  ['Paris', 'one One', 'whatever else'],
  ['Paris', 'one One', 'whatever else'],
  ['London', 'one One', 'whatever else'],
]

const onlyParis = yourArray.filter(function(array) {
  return array.includes('Paris')
})

console.log(onlyParis)