Mār*_*dis 12
好的,我想我找到了你:
$days = cal_days_in_month(CAL_GREGORIAN, 1, 2011);
$week_day = date("N", mktime(0,0,0,1,1,2011));
$weeks = ceil(($days + $week_day) / 7);
echo $weeks;
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此代码返回一个月的天数.
<?php
for ($year = 2011; $year <= 2012; $year++){
for ($month = 1; $month <= 12; $month++){
$num_of_days = date("t", mktime(0,0,0,$month,1,$year));
$month_Year = date("F",mktime(0, 0, 0, $month, 1, $year));
echo "<b>$month_Year, $year </b><BR>";
echo "Number of days = $num_of_days <BR>";
$firstdayname = date("D", mktime(0, 0, 0, $month, 1, $year));
$firstday = date("w", mktime(0, 0, 0, $month, 1, $year));
$lastday = date("t", mktime(0, 0, 0, $month, 1, $year));
$lastdayname = date("D", mktime(0, 0, 0, $month, $lastday, $year));
echo "First day of the month = $firstday,$firstdayname <BR> ";
echo "Last day of the month = $lastday,$lastdayname <BR> ";
$no_of_weeks = 1;
$count_weeks = 0;
while($no_of_weeks <= ($lastday+$firstday)){
$no_of_weeks += 7;
$count_weeks++;
}
echo "Number Of weeks = $count_weeks <br><br>";
}
}
?>
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