m_r*_*uby 9 javascript arrays lodash
我正在尝试将课程与用户进度数据合并.我相信我有指针问题.
我已经成功完成了两个数组的内部合并.问题在于循环访问用户而没有获得附加进度数据的正确课程数据.
let lessons = [
{“id”: “0106c568-70c0-4e56-8139-8e7f7d124f95",},
{“id”: “033e18a2-d470-4fd7-8bdc-53e610f3f784",},
{“id”: “d60f751c-d7d2-4dc6-9eda-a03bc5ebddc6",},
];
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const usersProgresses = [
[
{
“id”: “cjrtmj9d601b908559oxe8hwk”,
“lesson”: “0106c568-70c0-4e56-8139-8e7f7d124f95",
“score”: null,
},
{
“id”: “cjrtmk2hv01bx0855yof2ehj4”,
“lesson”: “033e18a2-d470-4fd7-8bdc-53e610f3f784”,
“score”: 100,
},
{
“id”: “cjrtmlohd01cp0855jnzladye”,
“lesson”: “3724d7df-311c-46d9-934f-a9c44d9335ae”,
“score”: 20,
}
],
...
];
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// for each user
const result = usersProgresses.map(user => {
// merge progress and lesson data by lesson.id
const mergedProgress = [...lessons].map(lesson => {
return _.merge(lesson,_ .find(userProgress, { lesson: lesson.id }));
});
return mergedProgress;
});
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预期数据来自result:
[
[
{
“id”: “0106c568-70c0-4e56-8139-8e7f7d124f95”,
“lesson”: “0106c568-70c0-4e56-8139-8e7f7d124f95”,
“score”: null,
},
{
“id”: “033e18a2-d470-4fd7-8bdc-53e610f3f784",
“lesson”: “033e18a2-d470-4fd7-8bdc-53e610f3f784",
“score”: 100,
},
{
“id”: “d60f751c-d7d2-4dc6-9eda-a03bc5ebddc6”,
}
]
]
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但得到:
[
[
{
“id”: “0106c568-70c0-4e56-8139-8e7f7d124f95”,
},
{
“id”: “033e18a2-d470-4fd7-8bdc-53e610f3f784”,
},
{
“id”: “d60f751c-d7d2-4dc6-9eda-a03bc5ebddc6”,
}
]
]
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你可以使用嵌套.map在vanilla js中做这样的事情:
const lessons = [{"id":"0106c568-70c0-4e56-8139-8e7f7d124f95",},{"id":"033e18a2-d470-4fd7-8bdc-53e610f3f784",},{"id":"d60f751c-d7d2-4dc6-9eda-a03bc5ebddc6",}]
const usersProgress = [[{"id":"cjrtmj9d601b908559oxe8hwk","lesson":"0106c568-70c0-4e56-8139-8e7f7d124f95","score":null,},{"id":"cjrtmk2hv01bx0855yof2ehj4","lesson":"033e18a2-d470-4fd7-8bdc-53e610f3f784","score":100,},{"id":"cjrtmlohd01cp0855jnzladye","lesson":"3724d7df-311c-46d9-934f-a9c44d9335ae","score":20,}]]
const output = usersProgress.map(user => lessons.map(lesson =>
({...user.find(p => p.lesson == lesson.id), ...lesson }))
);
console.log(output)Run Code Online (Sandbox Code Playgroud)