在Java中创建一个斜坡

Question

我试图在java中创建一个斜率.我可以使用DrawLine函数,它会创建一个完美的函数,但我不想使用它,而是为它创建自己的函数.问题是点之间有间隙.

import java.applet.Applet;
import java.awt.Graphics;

public class slope extends Applet{



    public void drawLine(int x1, int y1, int x2, int y2, Graphics g) {

        double m = (y2 - y1) / (double)(x2-x1);
        double y = y1;
        for (int x =x1; x < x2; x++) {

            drawPoint(x,(int)y,g);
            y +=m;
        }
    }


    public void paint(Graphics g) {
        drawLine(20, 10, 300, 700, g); //has spaces between the dots 
        g.drawLine(20, 10, 300, 700); //this is perfect


    }

    private void drawPoint(int x, int y, Graphics g) {

        g.drawLine(x, y, x, y);

    }
}

Answer 1

基于Bresenham算法，这里是一个 Java 实现，它假设x2 > x1 and y2 > y1并使用整数算术

import java.applet.Applet;
import java.awt.*;

public class Slope extends Applet{

    private int x1 = 20, y1 = 10;
    private int x2 = 300, y2 = 700;

    @Override
    public void paint(Graphics g) {

        drawLine(x1, y1, x2, y2, g);
        //g.drawLine(x1, y1, x2, y2, g);  

    }

    private void drawPoint(int x, int y, Graphics g) {
        g.drawLine(x,y,x,y);
   }

   @Override
    public void init(){
        this.setSize(500,700);
   }

    private void drawLine(int x1,int y1,int x2,int y2,Graphics g){

        int dx = x2 - x1;
        int dy = y2 - y1;
        int xi = 1;
        int D = 2*dx - dy;
        int x = x1;

        for(int y = y1; y <y2; y++) {
            drawPoint(x,y,g);
            if(D > 0) {
                x = x + xi;
                D = D - 2 * dy;
            }
                D = D + 2 * dx;
            }
        }
}