高效的字符串后缀检测

Sot*_*tos 7 python string-matching apache-spark apache-spark-sql pyspark

我正在使用PySpark处理一个庞大的数据集,我希望根据另一个数据框中的字符串过滤数据帧.例如,

dd = spark.createDataFrame(["something.google.com","something.google.com.somethingelse.ac.uk","something.good.com.cy", "something.good.com.cy.mal.org"], StringType()).toDF('domains')
+----------------------------------------+
|domains                                 |
+----------------------------------------+
|something.google.com                    |
|something.google.com.somethingelse.ac.uk|
|something.good.com.cy                   |
|something.good.com.cy.mal.org           |
+----------------------------------------+  

dd1 =  spark.createDataFrame(["google.com", "good.com.cy"], StringType()).toDF('gooddomains')
+-----------+
|gooddomains|
+-----------+
|google.com |
|good.com.cy|
+-----------+
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我认为domainsgooddomains有效的域名.

我想要做的是过滤掉dd不结束的匹配字符串dd1.所以在上面的例子中,我想过滤掉第1行和第3行,最后得到

+----------------------------------------+
|domains                                 |
+----------------------------------------+
|something.google.com.somethingelse.ac.uk|
|something.good.com.cy.mal.org           |
+----------------------------------------+  
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我目前的解决方案(如下所示)只能考虑最多3个字的域名.如果我要添加say,verygood.co.ac.ukin dd1(即白名单),那么它将失败.

def split_filter(x, whitelist):
    splitted1 = x.select(F.split(x['domains'], '\.').alias('splitted_domains'))
    last_two = splitted1.select(F.concat(splitted1.splitted_domains[F.size(splitted1.splitted_domains)-2], \
       F.lit('.'), \
       splitted1.splitted_domains[F.size(splitted1.splitted_domains)-1]).alias('last_two'))
    last_three = splitted1.select(F.concat(splitted1.splitted_domains[F.size(splitted1.splitted_domains)-3], \
       F.lit('.'), \
       splitted1.splitted_domains[F.size(splitted1.splitted_domains)-2], \
       F.lit('.'), \
       splitted1.splitted_domains[F.size(splitted1.splitted_domains)-1]).alias('last_three'))
    x = x.withColumn('id', F.monotonically_increasing_id())
    last_two = last_two.withColumn('id', F.monotonically_increasing_id())
    last_three = last_three.withColumn('id', F.monotonically_increasing_id())
    final_d = x.join(last_two, ['id']).join(last_three, ['id'])
    df1 = final_d.join(whitelist, final_d['last_two'] == whitelist['domains'], how = 'left_anti')
    df2 = df1.join(whitelist, df1['last_three'] == whitelist['domains'], how = 'left_anti')
    return df2.drop('id')
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我使用Spark 2.3.0和Python 2.7.5.

use*_*362 10

让我们扩展domains稍微更好的覆盖范围:

domains = spark.createDataFrame([
    "something.google.com",  # OK
    "something.google.com.somethingelse.ac.uk", # NOT OK 
    "something.good.com.cy", # OK 
    "something.good.com.cy.mal.org",  # NOT OK
    "something.bad.com.cy",  # NOT OK
    "omgalsogood.com.cy", # NOT OK
    "good.com.cy",   # OK 
    "sogood.example.com",  # OK Match for shorter redundant, mismatch on longer
    "notsoreal.googleecom" # NOT OK
], "string").toDF('domains')

good_domains =  spark.createDataFrame([
    "google.com", "good.com.cy", "alsogood.com.cy",
    "good.example.com", "example.com"  # Redundant case
], "string").toDF('gooddomains')
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现在...... 只使用Spark SQL原语的简单解决方案是简化当前的方法.既然您已经声明可以安全地假设这些是有效的公共域,我们可以定义这样的函数:

from pyspark.sql.functions import col, regexp_extract

def suffix(c): 
    return regexp_extract(c, "([^.]+\\.[^.]+$)", 1) 
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提取顶级域和第一级子域:

domains_with_suffix = (domains
    .withColumn("suffix", suffix("domains"))
    .alias("domains"))
good_domains_with_suffix = (good_domains
    .withColumn("suffix", suffix("gooddomains"))
    .alias("good_domains"))

domains_with_suffix.show()
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+--------------------+--------------------+
|             domains|              suffix|
+--------------------+--------------------+
|something.google.com|          google.com|
|something.google....|               ac.uk|
|something.good.co...|              com.cy|
|something.good.co...|             mal.org|
|something.bad.com.cy|              com.cy|
|  omgalsogood.com.cy|              com.cy|
|         good.com.cy|              com.cy|
|  sogood.example.com|         example.com|
|notsoreal.googleecom|notsoreal.googleecom|
+--------------------+--------------------+
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现在我们可以外连接:

from pyspark.sql.functions import (
    col, concat, lit, monotonically_increasing_id, sum as sum_
)

candidates = (domains_with_suffix
    .join(
        good_domains_with_suffix,
        col("domains.suffix") == col("good_domains.suffix"), 
        "left"))
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并过滤结果:

is_good_expr = (
    col("good_domains.suffix").isNotNull() &      # Match on suffix
    (

        # Exact match
        (col("domains") == col("gooddomains")) |
        # Subdomain match
        col("domains").endswith(concat(lit("."), col("gooddomains")))
    )
)

not_good_domains = (candidates
    .groupBy("domains")  # .groupBy("suffix", "domains") - see the discussion
    .agg((sum_(is_good_expr.cast("integer")) > 0).alias("any_good"))
    .filter(~col("any_good"))
    .drop("any_good"))

not_good_domains.show(truncate=False)     
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+----------------------------------------+
|domains                                 |
+----------------------------------------+
|omgalsogood.com.cy                      |
|notsoreal.googleecom                    |
|something.good.com.cy.mal.org           |
|something.google.com.somethingelse.ac.uk|
|something.bad.com.cy                    |
+----------------------------------------+
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这比直接连接所需LIKE笛卡尔积更好,但对蛮力不满意,在最坏的情况下需要两次洗牌 - 一次用于join(如果good_domains小到足够可以跳过broadcasted),另一次用于group_by+ agg.

不幸的是,Spark SQL不允许自定义分区器只为两者使用一次shuffle(但是在RDD API中可能使用复合键)并且优化器还不够智能,以进行优化join(_, "key1").groupBy("key1", _).

如果你能接受一些假阴性,你可以去概率化.首先让我们建立概率计数器(这里使用bounter小帮助toolz)

from pyspark.sql.functions import concat_ws, reverse, split
from bounter import bounter
from toolz.curried import identity, partition_all

# This is only for testing on toy examples, in practice use more realistic value
size_mb = 20      
chunk_size = 100

def reverse_domain(c):
    return concat_ws(".", reverse(split(c, "\\.")))

def merge(acc, xs):
    acc.update(xs)
    return acc

counter = sc.broadcast((good_domains
    .select(reverse_domain("gooddomains"))
    .rdd.flatMap(identity)
    # Chunk data into groups so we reduce the number of update calls
    .mapPartitions(partition_all(chunk_size))
    # Use tree aggregate to reduce pressure on the driver, 
    # when number of partitions is large*
    # You can use depth parameter for further tuning
    .treeAggregate(bounter(need_iteration=False, size_mb=size_mb), merge, merge)))
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接下来定义这样的用户定义函数函数

from pyspark.sql.functions import pandas_udf, PandasUDFType
from toolz import accumulate

def is_good_counter(counter):
    def is_good_(x):
        return any(
            x in counter.value 
            for x in accumulate(lambda x, y: "{}.{}".format(x, y), x.split("."))
        )

    @pandas_udf("boolean", PandasUDFType.SCALAR)
    def _(xs):
        return xs.apply(is_good_)
    return _
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并过滤domains:

domains.filter(
    ~is_good_counter(counter)(reverse_domain("domains"))
).show(truncate=False)
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+----------------------------------------+
|domains                                 |
+----------------------------------------+
|something.google.com.somethingelse.ac.uk|
|something.good.com.cy.mal.org           |
|something.bad.com.cy                    |
|omgalsogood.com.cy                      |
|notsoreal.googleecom                    |
+----------------------------------------+
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在Scala中,这可以完成bloomFilter

import org.apache.spark.sql.Column
import org.apache.spark.sql.functions._
import org.apache.spark.util.sketch.BloomFilter

def reverseDomain(c: Column) = concat_ws(".", reverse(split(c, "\\.")))

val checker = good_domains.stat.bloomFilter(
  // Adjust values depending on the data
  reverseDomain($"gooddomains"), 1000, 0.001 
)

def isGood(checker: BloomFilter) = udf((s: String) => 
  s.split('.').toStream.scanLeft("") {
    case ("", x) => x
    case (acc, x) => s"${acc}.${x}"
}.tail.exists(checker mightContain _))


domains.filter(!isGood(checker)(reverseDomain($"domains"))).show(false)
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+----------------------------------------+
|domains                                 |
+----------------------------------------+
|something.google.com.somethingelse.ac.uk|
|something.good.com.cy.mal.org           |
|something.bad.com.cy                    |
|omgalsogood.com.cy                      |
|notsoreal.googleecom                    |
+----------------------------------------+
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如果需要,不应该很难从Python调用这样的代码.

由于近似性质,这可能仍然不完全令人满意.如果您需要精确的结果,可以尝试利用数据的冗余特性,例如使用trie(此处使用datrie实现).

如果good_domains相对较小,您可以使用与概率变量类似的方式创建单个模型:

import string
import datrie


def seq_op(acc, x):
    acc[x] = True
    return acc

def comb_op(acc1, acc2):
    acc1.update(acc2)
    return acc1

trie = sc.broadcast((good_domains
    .select(reverse_domain("gooddomains"))
    .rdd.flatMap(identity)
    # string.printable is a bit excessive if you need standard domain
    # and not enough if you allow internationalized domain names.
    # In the latter case you'll have to adjust the `alphabet`
    # or use different implementation of trie.
    .treeAggregate(datrie.Trie(string.printable), seq_op, comb_op)))
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定义用户定义的函数:

def is_good_trie(trie):
    def is_good_(x):
        if not x:
            return False
        else:
            return any(
                x == match or x[len(match)] == "."
                for match in trie.value.iter_prefixes(x)
            )

    @pandas_udf("boolean", PandasUDFType.SCALAR)
    def _(xs):
        return xs.apply(is_good_)

    return _
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并将其应用于数据:

domains.filter(
    ~is_good_trie(trie)(reverse_domain("domains"))
).show(truncate=False)
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+----------------------------------------+
|domains                                 |
+----------------------------------------+
|something.google.com.somethingelse.ac.uk|
|something.good.com.cy.mal.org           |
|something.bad.com.cy                    |
|omgalsogood.com.cy                      |
|notsoreal.googleecom                    |
+----------------------------------------+
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这种特定的方法在假设所有good_domains可以压缩成单个线索的情况下工作,但是可以容易地扩展以处理不满足该假设的情况.例如,您可以为每个顶级域或后缀构建一个trie(如天真解决方案中所定义)

(good_domains
    .select(suffix("gooddomains"), reverse_domain("gooddomains"))
    .rdd
    .aggregateByKey(datrie.Trie(string.printable), seq_op, comb_op))
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然后,根据需要从序列化版本加载模型,或使用RDD操作.

可以根据数据,业务要求(如近似解决方案中的假负容差)和可用资源(驱动程序内存,执行程序内存,基数suffixes,访问分布式POSIX兼容的分布式文件系统)进一步调整这两种非本机方法, 等等).在应用这些DataFramesRDDs(内存使用,通信和序列化开销)之间进行选择时,还需要考虑一些权衡因素.


*请参阅了解Spark中的treeReduce()


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