函数返回名称不以 async 结尾的 Deferred

Question

我最近正在尝试学习 Kotlin 协程，我注意到在返回一堆asyncIDE的地图的情况下，显示消息说Function returning Deferred with a name that does not end with async. 这是我的代码

runBlocking {
    try {
        val siteDeferred = async { getSite(order) }
        // Place where I get warning-----------| (Function returning Deferred with a name that does not end with Async)
        //                                     v
        val orderLineDeferred = order.line.map { async { getOrderDetail(it) } }

        // Place where I get warning-------------------| (Function returning Deferred with a name that does not end with Async)
        //                                             v
        val orderLineProductsDeferred = order.line.map { async { getOrderProductInformation(it.productId) } }

        val site = siteDeferred.await()
        val orderLine = orderLineDeferred.awaitAll()
        val orderLineProducts = orderLineProductsDeferred.awaitAll()
    } catch (e: Throwable) {
        throw Exception(e.message)
    }
}

private suspend getOrderDetail(OrderLine orderLine): OrderDetail...
private suspend getSite(Order order): Site ...
private suspend getOrderProductInformation(String productId): Product ...

我在这里错过了什么吗？此外，我想知道这是否是进行异常处理的正确方法，有没有办法清理try块，以便我可以直接获取值，即使这意味着我必须async在其他方法中使用。

Answer 1

函数getSite()重命名为getSiteAsync() ?其他函数以这种方式修改。