Kusto：如何从不参与 SUMMARIZE 的列中获取值？

Question

有了下表和 Kusto 查询，如何获得包含“购买”列的结果？

let ProductsTable = datatable(Supplier: string, Fruit: string, Price: int, Purchase: datetime)
[
    'Contoso', 'Grapes', 220, datetime(2018-10-01 01:00),
    'Fabrikam', 'Lemons', 31, datetime(2018-10-01 02:00),
    'Contoso', 'Lemons', 29, datetime(2018-10-02 03:00),
    'Contoso', 'Grapes', 210, datetime(2018-10-02 04:00),
    'Fabrikam', 'Lemons', 30, datetime(2018-10-03 05:00),
    'Contoso', 'Bananas', 12, datetime(2018-10-03 06:00),
    'Contoso', 'Bananas', 12, datetime(2018-10-04 07:00),
    'Contoso', 'Lemons', 29, datetime(2018-10-04 08:00),
    'Contoso', 'Grapes', 200, datetime(2018-10-05 09:00),
];
ProductsTable
    | summarize Price = min(Price) by Supplier, Fruit
    | order by Supplier asc, Fruit asc, Price asc

结果

Contoso Bananas 12
Contoso Grapes      200
Contoso Lemons      29
Fabrikam    Lemons      30

期望的结果

Contoso Bananas 12  2018-10-03 06:00
Contoso Grapes      200 2018-10-05 09:00
Contoso Lemons      29  2018-10-02 03:00
Fabrikam    Lemons      30  2018-10-03 05:00

我知道可能有多个结果，例如对于Contoso-Bananas-12，我们可以有以下任何结果

• 2018-10-03 0 6 :00
• 2018-10-04 0 7 :00

Answer 1

尝试使用arg_min()：https ://learn.microsoft.com/en-us/azure/kusto/query/arg-min-aggfunction

let ProductsTable = datatable(Supplier: string, Fruit: string, Price: int, Purchase: datetime)
[
    'Contoso', 'Grapes', 220, datetime(2018-10-01 01:00),
    'Fabrikam', 'Lemons', 31, datetime(2018-10-01 02:00),
    'Contoso', 'Lemons', 29, datetime(2018-10-02 03:00),
    'Contoso', 'Grapes', 210, datetime(2018-10-02 04:00),
    'Fabrikam', 'Lemons', 30, datetime(2018-10-03 05:00),
    'Contoso', 'Bananas', 12, datetime(2018-10-03 06:00),
    'Contoso', 'Bananas', 12, datetime(2018-10-04 07:00),
    'Contoso', 'Lemons', 29, datetime(2018-10-04 08:00),
    'Contoso', 'Grapes', 200, datetime(2018-10-05 09:00),
];
ProductsTable
| summarize Price = arg_min(Price, *) by Supplier, Fruit
| order by Supplier asc, Fruit asc, Price asc