tidyverse：一个变量与 data.frame 中所有其他变量的交叉表

Question

我想制作一个变量与 data.frame 中所有其他变量的交叉表。

library(tidyverse)
library(janitor)

humans <- starwars %>%
  filter(species == "Human")

humans %>%
  janitor::tabyl(gender, eye_color)



gender blue blue-gray brown dark hazel yellow
 female    3         0     5    0     1      0
   male    9         1    12    1     1      2

humans %>%
  dplyr::select_if(is.character) %>%
  dplyr::select(-name, -gender) %>%
  purrr::map(.f = ~janitor::tabyl(dat = humans, gender, .x))

Error: Unknown columns `blond`, `none`, `brown`, `brown, grey`, `brown` and ... 
Call `rlang::last_error()` to see a backtrace

Answer 1

tably将名称作为参数，并向其传递一个向量。

如果使用，imap您将可以访问列的名称，您可以将其转换为符号，并且janitor支持准引用，您可以编写：

humans %>%
  select_if(is.character) %>%
  select(-name, -gender) %>%
  imap(.f = ~janitor::tabyl(dat = humans, !!sym(.y), gender))
#$`hair_color`
#     hair_color female male
#         auburn      1    0
#   auburn, grey      0    1
#  auburn, white      0    1
#          black      1    7
#          blond      0    3
#          brown      6    8
#    brown, grey      0    1
#           grey      0    1
#           none      0    3
#          white      1    1
# 
# $skin_color
#  skin_color female male
#        dark      0    4
#        fair      3   13

有趣的是tabyl.data.frame，调用一个对符号起作用的未导出函数，因此通过直接调用它，我们可以跳过取消引用并使用基本 R。

cols <- setdiff(names(Filter(is.character,humans)), c("name","gender"))
lapply(cols, function(x) janitor:::tabyl_2way(humans, as.name(x), quote(gender)))
# [[1]]
#     hair_color female male
#         auburn      1    0
#   auburn, grey      0    1
#  auburn, white      0    1
#          black      1    7
#          blond      0    3
#          brown      6    8
#    brown, grey      0    1
#           grey      0    1
#           none      0    3
#          white      1    1
# 
# [[2]]
#  skin_color female male
#        dark      0    4

为了使其与xtable@akrun 的建议一起工作，这里也适用：

humans %>%
  select_if(is.character) %>%
  select(-name, -gender) %>%
  imap(.f = ~tabyl(dat = humans, !!sym(.y), gender) %>% rename_at(1,~"x")) %>%
  xtableList

或者

cols <- setdiff(names(Filter(is.character,humans)), c("name","gender"))
l <- lapply(cols, function(x) {
  res <- janitor:::tabyl_2way(humans, as.name(x), quote(gender))
  names(res)[1] <- "x"
  res
})
xtableList(l)